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prisoha [69]
2 years ago
14

Let f(x)=2x^2-2x+7 and g(x) =x^2 +9x-6. Find f(x)-g(x)

Mathematics
2 answers:
Andreyy892 years ago
7 0

Answer:

x² - 11x + 13

Step-by-step explanation:

f(x) - g(x)

= 2x² - 2x + 7 - (x² + 9x - 6) ← distribute by - 1

= 2x² - 2x + 7 - x² - 9x + 6 ← collect like terms

= x² - 11x + 13

Helga [31]2 years ago
5 0

Step-by-step explanation:

hi im not really sure if this is right

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Answer:

rounded to the nearest ten thousand

2,034,627

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The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?
VARVARA [1.3K]

Answer:

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Step-by-step explanation:

we are given a quadratic function

\displaystyle f(x) =  - 5 {x}^{2}  + 30x - 200

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

\displaystyle x _{ \rm  min} =  \frac{ - b}{2a}

the given function is in the standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

so we acquire:

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thus substitute:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{2. - 5}

simplify multiplication:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{ - 10}

simply division:

\displaystyle x _{ \rm  min} =  3

plug in the value of minimum x to the given function:

\displaystyle f (3)=  - 5 {(3)}^{2}  + 30.3 - 200

simplify square:

\displaystyle f (3)=  - 5 {(9)}^{}  + 30.3 - 200

simplify multiplication:

\displaystyle f (3)=  - 45  + 90- 200

simplify:

\displaystyle f (3)=   - 155

hence,

the minimum value of the function is -155

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2 years ago
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