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Minchanka [31]
3 years ago
15

Given a population that contains genetic variation, what is the correct sequence of the following events under the influence of

natural selection? 1. Well-adapted individuals leave more offspring than do poorly adapted individuals. 2. A change occurs in the environment. 3. Genetic frequencies within the population change. 4. Poorly adapted individuals have decreased survivorship. Group of answer choices
Biology
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

2. A change occurs in the environment.

4. Poorly adapted individuals have decreased survivorship.

1. Well-adapted individuals leave more offspring than do poorly adapted individuals.

3. Genetic frequencies within the population change.

Explanation:

The natural selection theory was developed by Darwin to explain how evolution occur within a population. The environment is in constant state of changes and always select for organisms that are better adapted to it.

Poorly adapted organisms gradually reduce from the population as a result of decreased survival while well-adapted individuals multiply and contribute more to successive generation.

Well-adapted individuals pass on the adaptive alleles to their offspring, eventually leading to a change in gene frequencies within the population.

Hence, the sequence of events is 2, 4, 1 and 3.

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Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

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