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3 years ago

Targeted 10

Mathematics

1 answer:

Nataly [62]3 years ago

5 0

Answer:

not enough info

Step-by-step explanation:

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I need a little help with this problem: 5k + 1 = 4k - 1

Varvara68 [4.7K]

5k-4k=-1+-1
k=-2, its all aboit rearranging the order of numders based on there like terms. If you need any more help ask.

8 0

3 years ago

700% of what number is 154? Show ALL of your work.

lesantik [10]

Answer:

1,078

Step-by-step explanation:

700 x 154= 107800

1078.00

3 0

3 years ago

The regular price of a scooter is $65.50. It is on sale for $52.40. What is the percent

kherson [118]

Answer:

20%

Step-by-step explanation:

First we find the actual dollar amount of the discount.

$65.50 - $52.40 = $13.10

Now we need to find what percent of $65.50 is $13.10.

To find what percent a part is of the whole, divide the part by the whole and multiply by 100%.

percent = part/whole * 100%

percent = $13.10/$65.50 * 100% = 20%

Answer: 20%

4 0

3 years ago

Read 2 more answers

I need help with this problem for math plz

san4es73 [151]

I need to see the shape so I can help

7 0

2 years ago

Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0

BartSMP [9]

The power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

$\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}$

We can write g(x) as,

$\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\$

We know that, $\frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n}$ if |x| < 1

and $\frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n$ if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\$ if |x| < 1 and if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$ if |x| < 1

Therefore, the power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0

2 years ago