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3 years ago

Which features involve compression? Select the three correct answers.

Physics

2 answers:

motikmotik3 years ago

4 0

B. Anticlines C. Folded mountains E. Monoclines that's the answer.

kirill [66]3 years ago

3 0

Answer: Option (A), (B), (C) and (E)

Explanation:

Reverse faults are those in which the hanging wall goes up and the footwall goes down due to the compressional forces.
Anticlines are formed due to compression on the limbs in which older rocks are at the bottom and younger rocks are at the top.
Folded mountains are formed due to the collision between two continental plates such as the Himalayas.
Normal faults are the common faults where hanging wall goes down and footwall remains up due to action of tensional forces.
Monoclines are folds that are subjected to smaller compressional force and one of its limb lies in a horizontal manner.

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4 years ago

Scientists have investigated how quickly hoverflies start beating their wings when dropped both in complete darkness and in a li

Vesna [10]

Answers:

A) 0.204 m

B) 0.285 s

Explanation:

<h2>Answer A:</h2>

This described situation is free fall, this means the initial velocity of the fly is zero, and the equation that will be used is:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y$ is the final height of the fly

$y_{o}=40 cm=0.4 m$ is the initial height of the fly

$V_{o}=0$ is the initial velocity of the fly

$t=200(10)^{-3} s$ is the time

$g=9.8 m/s^{2}$ is the acceleration due to gravity

$y=0.4 m+0-\frac{1}{2}(9.8 m/s^{2})(200(10)^{-3} s)^{2}$ (2)

$y=0.204 m$ (3) This is the distance at which the fly would begin to beat its wings

<h2>Answer B:</h2>

In this part we will also use equation (1), but we will find the time:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0$ is the final height of the fly

$y_{o}=40 cm=0.4 m$ is the initial height of the fly

$V_{o}=0$ is the initial velocity of the fly

$t$ is the time we need to find

$g=9.8 m/s^{2}$ is the acceleration due to gravity

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Isolating $t$ :

$t^{2}=\frac{(-2)(-0.4 m)}{9.8 m/s^{2}}$ (5)

$t=0.285 s$ (6) This is the time it would take for a fly to hit the bottom of the box

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4 years ago

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andrew-mc [135]

Let us first find out the radioactive constant of Phosphorus 32.

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= $4*e^{-ln(2)^{5}}$

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= $\frac{4}{32}$

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