Question

A 4kg watermelon is dropped from a height of 45m. What is the velocity of the watermelon just before it hits the ground?

Answer 1

Answer:

v=30 m/s

Explanation:

h - height

g - acceleration due to gravity=10

t - time

v- velocity

$h = \frac{1}{2} \times g \times t {}^{2}$

45 = 5t²

t² = 9

t=3 seconds

v=g×t

v=10×3

v=30 m/s