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3 years ago

Estimate the unit rate if 12 pairs of socks sell for $5.79

Mathematics

1 answer:

elena55 [62]3 years ago

8 0

You divide the amount by total price for the unit rate. 5.79$ divided by 12, is about 0.48 or .48 cents.

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FIVE STARS AND BRAINLIEST FOR CORRECT ANSWER

Charra [1.4K]

For the given vectors $\vec{a}=a_{1}\hat{i}+a_{2}\hat{j}$ and $\vec{b}=b_{1}\hat{i}+b_{2}\hat{j}$

The dot product of vectors a and b is defined as = $\vec{a}.\vec{b}=(a_{1}\times b_{1}+a_{2} \times b_{2})$

So, $\vec{a}.\vec{b} = (4\hat{i}+3\hat{j}). (-4\hat{i}+4\hat{j})$

$\vec{a}.\vec{b}=(4\times(-4)+3 \times4)$

= -16+12

= -4

8 0

3 years ago

The pairs 3, 12 and 4, 9 are factor pairs of which number? A) 32 B) 36 C) 44 D) 82

KatRina [158]

Answer:

$\Huge \boxed{\mathrm{B) \ 36}}$

$\rule[225]{225}{2}$

Step-by-step explanation:

A pair of factors are two factors of a number, when multiplied, gives the number.

$3* 12=36$

$4*9=36$

The pairs 3, 12 and 4, 9 are factor pairs of 36.

$\rule[225]{225}{2}$

6 0

3 years ago

Read 2 more answers

Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9

mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that $\mu = 20.5, \sigma = 0.9$