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Travka [436]
3 years ago
12

250 kids go to the local pool on a hot summers day. Each kid dives off the diving board 9 times. How many dives are there altoge

ther?
Mathematics
2 answers:
Paraphin [41]3 years ago
4 0
<h3>Answer: </h3>

2250 dives

<h3>Explanation</h3>

If each kid dives off the diving board 9 times, for 250 kids, you need to resolve a simple operation:

9 \times 250 = 2250

Pani-rosa [81]3 years ago
3 0

2250 dives all together

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What is the value of x?<br><br> This is the last question I don’t get
Stels [109]

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The answer is 166

Step-by-step explanation:

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Use Synthetic substitution to find f(3) and f(-4) for f(x)=x^4-8x-11
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Answer:

46 and 277

Step-by-step explanation:

Given

f(x) = x^{4} - 8x - 11 ← substitute x = 3, x = - 4 into f(x)

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3 years ago
Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
Mice21 [21]

Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

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m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

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1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

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NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

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\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

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3 years ago
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Use two unit multipliers to convert 628 kilometers to centimeters
irina [24]

Using two unit multiplier 628 km is equal to 62800000 cm

<u>Solution:</u>

628 kilometer to centimeter

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Now the km's will cancel:

\frac{628}{1} \times \frac{1000m}{1}

Now we want to get rid of m and bring in cm.

We know that 100 cm = 1 m.

Since meter is in the numerator, we will make the  first unit multiplier by putting 1 meter in the  denominator and 100 cm in the numerator, so the  meter's will cancel. So we multiply by the unit  multiplier

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628 \times 1000 \times 100 cm

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5 0
4 years ago
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