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photoshop1234 [79]
2 years ago
14

What is the measure of the smallest interior angle of the hexagon shown?

Mathematics
1 answer:
yan [13]2 years ago
7 0
<h3>Answer:  C) 70 degrees</h3>

=========================================================

Explanation:

We have n = 6 sides, so the interior angles must add to 180(n-2) = 180(6-2) = 720 degrees

Lets add up the angles, set the sum equal to 720 and solve for x

x+2x+115+2x+115+2x = 720

7x+230 = 720

7x = 720-230

7x = 490

x = 490/7

x = 70

This makes angle 2x = 2*70 = 140 degrees

We see that x = 70 is the smallest angle, so that's why C is the answer.

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How many times dose 3 go in to 81
puteri [66]
3 goes into 81, 27 times.
6 0
3 years ago
Read 2 more answers
Please help me will give branlist
MatroZZZ [7]

Answer: 36 hotdogs

Step-by-step explanation: You need to find the least common multiple of 9 and 12.

You can check by multiplying 9 and 12 by consecutive whole numbers until you find a number that they match.

Example:

9*1= 9 , 9*2=18, 9*3= 27, 9*4=36, 9*5=45

12*1=12, 12*2=24, 12*3 =36

They both share 36.

7 0
3 years ago
Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4
gtnhenbr [62]

Answer:

Simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

Step-by-step explanation:

We need to simplify the expression (6^{-2})(3^{-3})(3*6)^4

Solving:

(6^{-2})(3^{-3})(3*6)^4

Applying exponent rule: a^{-m}=\frac{1}{a^m}

=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\

Factors of 18=2\times 3\times 3=2\times3^2

Factors of 6=2\times 3

Replacing terms with factors

=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\

Using exponent rule: (a^m)^n=a^{m\times n}

=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}

Using exponent rule: a^m.a^n=a^{m+n}

=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}

Now using exponent rule: \frac{a^m}{a^n}=a^{m-n}

=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108

So, simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

7 0
3 years ago
The base of a triangle is seven less than twice its height. If the area of the triangle is 100cm^2 find the length of the base
Alexeev081 [22]
2x-7 * x
----------- =. 100^2= 10000 
     2


2x^2-7/2= x^2-7/2

x^2-7/2=10000

x^2 = 20007/7
7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%2064%2F4" id="TexFormula1" title="\sqrt{x} 64/4" alt="\sqrt{x} 64/4" align="abs
ozzi

Answer: =16\sqrt{x}

Step-by-step explanation:

\sqrt{x}\frac{64}{4}=16\sqrt{x}

8 0
2 years ago
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