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2 years ago

What is the measure of the smallest interior angle of the hexagon shown?

Mathematics

1 answer:

yan [13]2 years ago

7 0

<h3>Answer: C) 70 degrees</h3>

=========================================================

Explanation:

We have n = 6 sides, so the interior angles must add to 180(n-2) = 180(6-2) = 720 degrees

Lets add up the angles, set the sum equal to 720 and solve for x

x+2x+115+2x+115+2x = 720

7x+230 = 720

7x = 720-230

7x = 490

x = 490/7

x = 70

This makes angle 2x = 2*70 = 140 degrees

We see that x = 70 is the smallest angle, so that's why C is the answer.

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How many times dose 3 go in to 81

puteri [66]

3 goes into 81, 27 times.

6 0

3 years ago

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Please help me will give branlist

MatroZZZ [7]

Answer: 36 hotdogs

Step-by-step explanation: You need to find the least common multiple of 9 and 12.

You can check by multiplying 9 and 12 by consecutive whole numbers until you find a number that they match.

Example:

9*1= 9 , 9*2=18, 9*3= 27, 9*4=36, 9*5=45

12*1=12, 12*2=24, 12*3 =36

They both share 36.

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3 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

3 years ago

The base of a triangle is seven less than twice its height. If the area of the triangle is 100cm^2 find the length of the base

Alexeev081 [22]

2x-7 * x
----------- =. 100^2= 10000
2

2x^2-7/2= x^2-7/2

x^2-7/2=10000

x^2 = 20007/7

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3 years ago

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%2064%2F4" id="TexFormula1" title="\sqrt{x} 64/4" alt="\sqrt{x} 64/4" align="abs

ozzi

Answer: $=16\sqrt{x}$

Step-by-step explanation:

$\sqrt{x}\frac{64}{4}=16\sqrt{x}$

8 0

2 years ago