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Alex
3 years ago
8

Which inequality is equivalent to -3x < -12?

Mathematics
1 answer:
astraxan [27]3 years ago
8 0

Answer:

Simplified, this will be equal to x>4.

Step-by-step explanation:

I assume you need it simplified, since not much information was provided. Here is how you would do that:

-3x<-12

Divide by -3

Swap inequality sign since you are dividing by a negative

x>4

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Select all equivelent to the following: 9y+4y+9y<br> 1. 22y<br> 2. 13y-9y<br> 3. 9y+13y<br> 4. 22+y
igor_vitrenko [27]

Answer: 22y and 9y+13y

Step-by-step explanation: Just using basic math, ofc

1st Answer: 9y + 9y = 18y .

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2 years ago
For an independent t-test, if the mean of group 1=10, mean of group 2=12, ss1 =5, ss2=8, there are 6 individuals per group. what
eimsori [14]

The value of t obtained is 4.76

Given,

Mean of group 1, M_{1} = 10

Mean of group 2, M_{2} = 12

SS_{1} = 5

SS_{2} = 8

Number of individuals per group, n = 6

The degrees of freedom are calculated as:

df = (n_{1} -1)+(n_{2} -1) = ( 8-1) + (8-1) = 7 + 7 = 14

The difference between sample means M_{d} is:

M_{d} = M_{1} -M_{2} = 10 - 12 = 2

Here n is equal for both groups which is = 8

Now,

The standard deviation of sample 1 :

s_{1} =\sqrt{\frac{SS_{1} }{n_{1} -1} } = \sqrt{\frac{5}{8-1} } = \sqrt{\frac{5}{7} } = 0.85

The standard deviation of sample 2 :

s_{2}= \sqrt{\frac{SS_{2} }{n_{2}-1 } } = \sqrt{\frac{8}{8-1} } = \sqrt{\frac{8}{7} } = 1.07

Now, we have to calculate the standard error for the difference of the means.

MSE = \frac{(n_{1}-1)s^{2} _{1}+(n_{2}-1)s^{2} _{2}    }{(n_{1}-1)+(n_{2}-1)  }

       = \frac{(8-1)(0.85^{2})+(8-1)(1.07^{2})  }{(8-1)+(8-1)}

       = \frac{10.1318}{14}

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Then, the standard error can be calculated as:

s_{M_{d} } = \sqrt{\frac{2MSE}{n} } = \sqrt{\frac{2  * 0.7237}{8} } = 0.42

Now we can calculate t :

t=\frac{M_{d} }{s_{M_{d} } } = \frac{2}{0.42} = 4.76

Learn more about standard deviation here : brainly.com/question/16403666

#SPJ4

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