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Bingel [31]
3 years ago
10

A ball is thrown from ground level straight up into the air at an intitial velocity of 54 feet per second. The height of the bal

l t seconds after it is thrown is given by the formula h(t)=54t-16’2. How many seconds after the ball is thrown will it return to the ground
Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Answer:

3 3/8 seconds.

Step-by-step explanation:

When it reaches the ground h = 0 so:

54t - 16t^2 = 0

16t^2 - 54t = 0

2t(8t - 27) = 0

t = 0 or t =  27/8   (we ignore the t = 0 ) so:

t =   3 3/8 seconds.

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77julia77 [94]
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Step 1: 
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 2: 
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 3: 
Place parentheses around the numbers above and below the median. 
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).

Step 4: 
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7),  9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.

Step 5: 
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
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