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Bingel [31]
3 years ago
10

A ball is thrown from ground level straight up into the air at an intitial velocity of 54 feet per second. The height of the bal

l t seconds after it is thrown is given by the formula h(t)=54t-16’2. How many seconds after the ball is thrown will it return to the ground
Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Answer:

3 3/8 seconds.

Step-by-step explanation:

When it reaches the ground h = 0 so:

54t - 16t^2 = 0

16t^2 - 54t = 0

2t(8t - 27) = 0

t = 0 or t =  27/8   (we ignore the t = 0 ) so:

t =   3 3/8 seconds.

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Answer:

2 years

Step-by-step explanation:

Let B = age on Ben

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How are dilations and functions related?
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3 years ago
Solve for x :)<br> 6x + 4x – 6 = 24 + 9x
Blababa [14]

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5 0
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Alexus [3.1K]

Answer:=

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Interval Notation: (-2,3)

Step-by-step explanation:

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