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Bingel [31]
3 years ago
10

A ball is thrown from ground level straight up into the air at an intitial velocity of 54 feet per second. The height of the bal

l t seconds after it is thrown is given by the formula h(t)=54t-16’2. How many seconds after the ball is thrown will it return to the ground
Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Answer:

3 3/8 seconds.

Step-by-step explanation:

When it reaches the ground h = 0 so:

54t - 16t^2 = 0

16t^2 - 54t = 0

2t(8t - 27) = 0

t = 0 or t =  27/8   (we ignore the t = 0 ) so:

t =   3 3/8 seconds.

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Question 24:

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<u>Question number 23:</u>

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subtracting 6x from both sides

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So

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As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

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