4 years ago

What is the discount rate for a $120.00 camera that is on sale for $105.00?

1 answer:

7 0

<span>The resent value, also called "discounted value," is the current worth of the camera. So, we know that the discounted value is $105.00.
The first price of the camera was $120.00.
This means that the price is decreased. In order to calculate the discount rate we should find out how many percent the camera was discounted. 105 from 120 is: 105/120*100=87.5
So, the discount is 100-87.5=12.5 %.
</span>

You might be interested in

It takes Austin 8 hours longer than Elliott to construct a wooden chair in shop class. When the classmates work together, they c

Scorpion4ik [409]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I need help on this, thank you in advance

Montano1993 [528]

Answer:

Step-by-step explanation:

yeah-ya........ right?

3 0

3 years ago

Email me in school ima bored Raul.Hoffman2d11.org<br> the 2 is the at wont let me

butalik [34]

Answer:

Step-by-step explanation:

4 0

3 years ago

Solve for x. (e^x-e^-x)/((e^x+e^-x)=t

Sergio [31]

$\dfrac{e^x-e^{-x}}{e^x+e^{-x}}=t\\\\
\dfrac{e^{2x}-1}{e^{2x}+1}=t\\\\
e^{2x}-1=t(e^{2x}+1)\\\\
e^{2x}-1=e^{2x}t+t\\\\
e^{2x}-e^{2x}t=t+1\\\\
e^{2x}(1-t)=t+1\\\\
e^{2x}=\dfrac{t+1}{1-t}\\\\
e^{2x}=-\dfrac{t+1}{t-1}\\\\
2x=\ln\left(-\dfrac{t+1}{t-1}\right)\\\\
x=\dfrac{\ln\left(-\dfrac{t+1}{t-1}\right)}{2}\qquad t\in(-1,1)



$