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4 years ago

Solve for x in the diagram below

Mathematics

2 answers:

Aleksandr [31]4 years ago

8 0

Answer:

x=20

Step-by-step explanation:

You make an equation (4x+100=180) and solve

4x=80---> x=20

DanielleElmas [232]4 years ago

4 0

Answer:

x = 20

Step-by-step explanation:

all of these together will come out to equal 180 degrees. Because it is a straight line. every straight lines is 180 degrees.

x + 3x + 100 = 180

simplify, 4x + 100 = 180

subtract 100 from both sides, 4x = 80

divide both sides by 4, x = 20

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3 shirts cost $54,how much was one shirt?

____ [38]

$18 (if each shirt costs the same, 54/3 = 18)

5 0

3 years ago

Read 2 more answers

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

Identify a pair of alternate exterior angles

mafiozo [28]

Answer:

2 and 6

Step-by-step explanation:

3 0

3 years ago

How do I solve this and what is the answer?

DanielleElmas [232]

Answer:

You use PEMDAS.

Step-by-step explanation:

If you dont know what that is, its the process used for long multistep equations like that : Parenthesis, Exponents, Multiplication, Division, Addition, then Subtraction. You solve all of those in order (if they are included in the problem). So for this you would solve one side of the inequality sign first using this order, then the other side and BAM! you've solved this problem.

8 0

3 years ago

In a school 30% of the teachers are math teachers. If there are 15 math teachers how many teachers are in the school?

AleksAgata [21]

Answer:

The total teachers in the school are 50.

Step-by-step explanation:

Given:

In a school math teachers are 30%.

Now, to get the total teachers in school if there are 15 math teachers.

Percentage of math teachers = 30%.

Number of math teachers = 15.