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kakasveta [241]
3 years ago
6

if you deposited $6500 into an account paying 8% annual interest compounded monthly how much money will be in the account after

7 years and 6 months make sure you round appropriately
Mathematics
1 answer:
inn [45]3 years ago
6 0

Answer:

it's going to be more than what I make

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Please help me to answer this question
ikadub [295]
(180-x) + 18 + 30 + x/2 = 180

=> 180 + 48 - x + x/2 = 180

=> -x/2 + 48 = 0

=> x/2 = 48

=> x = 48×2 = 96°
5 0
3 years ago
What THREE integers have a sum of 300?
quester [9]

Answer:

Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 300

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 300

3X + 3 = 300

3X + 3 - 3 = 300 - 3

3X = 297

3X/3 = 297/3

X = 99

Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.

99 + 100 + 101 = 300

We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please I need help ASAP
Allisa [31]

Answer:

it's 4.5

Step-by-step explanation:

you have to find the difference between each number and the mean. then you find the mean of that sum

4 0
2 years ago
Read 2 more answers
Please answer this asap.
vodomira [7]
The answer would be 39.78
4 0
2 years ago
Read 2 more answers
Please factor and find the zeros of each relation (18 marks)
AlekseyPX

Answer:

C. \ \frac{-2}{3} , \ \frac{-4}{5}\\\\D. \ -2, \ -4

Step-by-step explanation:

C.

30x^2 + 44x +16 = 0\\\\2(15x^2 + 22 + 8) = 0\\\\2(15x^2 + 12x + 10x + 8) = 0\\\\2(3x(5x + 4)+2(5x + 4))=0\\\\2((3x + 2)(5x + 4)) = 0\\\\Zeroes : 3x + 2 = 0 => x = \frac{-2}{3}\\

             5x+ 4 = 0 => x = \frac{-4}{5}

D.

10x^2 + 60x +80 = 0\\\\10(x^2 + 6x + 8)= 0\\\\10(x^2 + 4x + 2x + 8)=0\\\\10(x(x+4)+2(x+4))=0\\\\10((x+2)(x+4))=0\\\\Zeroes : x + 2 = 0 =>x = -2

            x + 4 = 0 => x= -4

3 0
2 years ago
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