Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
We have been given the equation:
And x=10
Substitute the given x in the given equation we get:
On simplification we get:
Required solution is: x= 10 and y=-20
The solution to the system of equation is those points that satisfy the given system of equations.
26
Hope this was helpful !
how many times does 5 go into 78
78/5
it goes 15 times with 3 left over (15*5 = 75 75+3 = 78)
15 3/5 ft
300. if you sold a third. then 2/3 would be left. you can then infer each is 300
