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GREYUIT [131]
3 years ago
5

What is the value of f(x) = 2 • 2^x for f(–2)? Will Give brainliest answer!!!

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0
For f(-2), x will equal -2.

Plug the x-value into the equation:

2 \times 2^{-2}

A negative exponent means that the term turns into a fraction, with 1 as the numerator and the positive exponent as the denominator. 
Solve 2^(-2):

2^{-2} =  \frac{1}{2^{2}} =  \frac{1}{4}

Solve the problem:

2 \times \frac{1}{4} = \frac{1}{2}

f(-2) will equal 1/2.
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3 years ago
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When 2(3/5 x + 2/3 y - 1/4 x -1 1/2 y + 3 )is simplified, what is the resulting expression?
vovangra [49]

Answer:

Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

Step-by-step explanation:

We need to simplify the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

First we will solve terms inside the bracket

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

Converting mixed fraction 1\frac{1}{2} y into improper fraction, we get: \frac{3}{2}y

Replacing the term:

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-\frac{3}{2}y +3)

Now, taking LCM of: 5,3,4,2 we get 60

Now multiply 60 with each term inside the bracket

2(\frac{3}{5}x\times60+\frac{2}{3}y\times60-\frac{1}{4}x\times60-\frac{3}{2}y\times60 +3\times60)\\2(3x\times12+2y\times20-1x\times15-3x\times30-3\times60)\\2(36x+40y-15x-90y-180)

Now, combine like terms

2(36x-15x-90y+40y-180)\\2(21x-50y-180)

Now, multiply all terms with 2

42x-100y-360

So, Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

3 0
3 years ago
What is the slope of the line that contains the point (13,-2) and (3,-2)
ra1l [238]

The slope of the line that contains the point (13,-2) and (3,-2) is 0

<em><u>Solution:</u></em>

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

<em><u>The slope of line is given as:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)

(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)

<em><u>Substituting the values in formula, we get,</u></em>

m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0

Thus the slope of line is 0

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