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fredd [130]
3 years ago
9

I need help on what equations is needed only, I know how to solve it and I just need help on # 13 noly

Mathematics
1 answer:
myrzilka [38]3 years ago
7 0
10 (> or = to)  2.00 + 0.75x

Sorry. I don't have that symbol on my keyboard. but her ten dollars has to be greater than or equal to whatever the cost is so that's why that symbol has to be used in this case. 2.00 is the flat rate and add 0.75 multiplied by however many miles she is taking!

Hope this helps!
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Free points, what is 2 + 2
Marina CMI [18]

Answer:

2+2=4 thank you and can I get brainlest too

4 0
3 years ago
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What is 2 3/5 minus 1 3/8 estimate the answer.
daser333 [38]
Find a common denominator first 

2 24/40 - 1 15/40 = 1 9/40 

it is already in simplest form so you can not reduce it
6 0
3 years ago
The Andromeda galaxy is 2.54 million (2.54x106) light years from earth. If light can travel 5.865 trillion (5.865x1012) miles in
Pavlova-9 [17]

Answer: 1.48971 x 10^19

Step-by-step explanation: 1-light year is approximately 5.865 x 10^12 which is 5,865,000,000,000 kilometers or 6 trillion miles in 1-year. The Andromeda galaxy is indeed 2.54 million light-years from Earth which is the closest galaxy to our Milky Way Galaxy.

The best way to this is to put this into a scientific calculator. If it shows 1.48971E19, the E stands for exponent and the 19 next to the E stands to the 19th power. That is written as 1,489,710,000,000,000,000 miles!! from Earth. That's a lot of zeros. That's the reason scientific notation is used; to avoid all those zeros and express very small/large figures.

Hope this explanation helps.

4 0
3 years ago
Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. What is the scale f
olasank [31]

Answer:

\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}

Step-by-step explanation:

A. Scale factor

When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

B. Length of EF

\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}

The area of its dilated image EFGH is

\text{Area of EFGH} = \text{147 in}^{2} \times \dfrac{\text{169}}{\text{49}} = 3 \times 169\text{ in}^{2} = 507 \text{ in}^{2}\\\\\text{The area of EFGH is $\large \boxed{\textbf{507 in}^{\mathbf{2}}}$}

8 0
3 years ago
Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (1,1). Express
gtnhenbr [62]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
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