All categories

3 years ago

Which choice shows the best estimate of the product 0.52×695 ?

Mathematics

1 answer:

evablogger [386]3 years ago

6 0

695 x .52 = 361.4
not sure if it's multiple choice, but this is what I got.

You might be interested in

A fair coin is tossed 20 times. The probability of getting the three or more heads in a row is 0.7870 and the probability of get

adelina 88 [10]

Answer:

The value is $P( H \ n \ T ) = 0.6049$

Step-by-step explanation:

From the question we are told that

The number of times is n = 20

The probability of getting three or more heads in a row is $P(H) = 0.7870$

The probability of getting three or more heads in a row or three or more tails in a row is $P(H \ u \ T ) = 0.9791$

Generally given that it is a fair coin , then $P(H) = P(T) = 0.7870$

Here P(T) is probability of getting three or more tails in a row

Generally the probability of getting three or more heads in a row and three or more tails in a row is mathematically represented as

$P( H \ n \ T ) = P(H) + P(T) - P( H \ u \ T )$

=> $P( H \ n \ T ) = 0.7870 + 0.7870 - 0.9791$

=> $P( H \ n \ T ) = 0.6049$

7 0

3 years ago

URGENT] <br>What is the perimeter of the figure? 28 m 22 m 20 m 14 m

egoroff_w [7]

Answer:

20m

Step-by-step explanation:

5+3+1+7+4=20

8 0

3 years ago

Is it possible to have an expression that uses brackets without using any parentheses???Explain.help plz

OverLord2011 [107]

Yes it is possible if it doesn't have parentheses

6 0

3 years ago

van budgets 12 a day for groceries for weekdays and 15 a day for weekends. write an expression in simplest form to show his groc

Ksenya-84 [330]

The budget of Van for groceries for 1 week is:

12 $ (per a weekday) * 5 (weekdays) + 15 $(per a weekend day) *2 (weekend days) = 60$ +30$ = 90$

The budget of Van for w weeks is:

90 $ (per week) * w (weeks) = 90w dollars.

Answer: 90w $

6 0

3 years ago

PLZ HELP ASAP! ILL MARK BRAINLEST!

Sav [38]

Question 1.) Factor completely $12x^{4}+ 6x^{3}+18x^{2}$

Since $6$ divides all the three terms of the equation, so we take $6$ common out from the equation.

i.e., $6(2x^{4}+ 1x^{3}+3x^{2})$

Now, since $x^{2}$ divides all the three terms of the equation, so we take $x^{2}$ common out from the equation.

i.e., $6x^{2}(2x^{2}+ 1x+3)$

Now, this cannot be factored further as $2x^{2}+ 1x+3$ is a quadratic equation and taking out discriminant of it is:

$D = (1)^2 - 4(2)(3)\\ \ \ = 1- 24\\ \ \ = -23$

Since, the discriminant is less than zero. Therefore, the factored form of the given equation : $12x^{4}+ 6x^{3}+18x^{2}$ is : $6x^{2}(2x^{2}+ 1x+3)$

Question 2.) $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$

Since $7$ divides all the three terms of the equation, so we take $7$ common out from the equation.

i.e., $7(x^{3}y+ 2x^{2} y^{3} - x^{2}y^{2})$

Now, since $x^{2}y$ divides all the three terms of the equation, so we take $x^{2}y$ common out from the equation.

i.e., $7x^{2}y(x+ 2y^{2} - y)$

Therefore, the factored form of the given equation : $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$ is : $7x^{2}y(x+ 2y^{2} - y)$

Question 3.) What is the Greatest Common Factor of $x^{6}$ and $x^{3}$ ?

The Greatest Common Factor of two numbers is the biggest number which divides both the given numbers completely.

Now, for the expressions $x^{6}$ and $x^{3}$ :

Since, $x^{3}$ divides both the expressions completely and it is the biggest expression which divides both the expressions.

Therefore, $x^{3}$ is the Greatest Common Factor of $x^{6}$ and $x^{3}$

7 0

3 years ago

Read 2 more answers