Answer:
Capacitive Reactance is 4 times of resistance
Solution:
As per the question:
R = 
where
R = resistance

f = fixed frequency
Now,
For a parallel plate capacitor, capacitance, C:

where
x = separation between the parallel plates
Thus
C ∝ 
Now, if the distance reduces to one-third:
Capacitance becomes 3 times of the initial capacitace, i.e., x' = 3x, then C' = 3C and hence Current, I becomes 3I.
Also,

Also,
Z ∝ I
Therefore,




Solving the above eqn:

Answer:
<em>UP</em>
Explanation:
heat flows from higher level to lower level
( higher concentration to lower concentration )
and since temperature in above block is less than the lower block, the heat will flow from lower block to higher block .
( Up )
^
|
|
|
----------->|
Square root of (4^2 + 4^2) = 4*squareRoot(2)
This is mr day and infact am seeing this… come into my office after class.
Answer:
9080 N
Explanation:
Consider the two motions of the ball.
In the downward motion, initial velocity, <em>u</em>, is 0 (because it falls from rest) and the distance is 28.7 m. Using the equation of motion and using <em>g</em> as 9.8 m/s²,
<em>v² = u² + 2as</em>
<em>v² = </em>0² + 2 × 9.8 × 28.7<em> </em>= 562.52
<em>v = </em>19.7 m/s
<em />
For the downward motion, the initial velocity is unknown, the final velocity is 0 and initial velocity is desired. <em>g</em> is negative because the motion is upwars.
<em>0² = v² - </em>2 × 9.8 × 19.8
<em>v² = </em>388.08
<em>v = </em>10.7 m/s
The change in momentum = 0.502(10.7 -(23.7)) = 21.7868 kgm/s
The impulse = change in monetum
Ft = 21.7868 kgm/s
But t = 2.4 ms
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