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Daniel [21]
2 years ago
10

Please solve the Problem.

Physics
1 answer:
aalyn [17]2 years ago
5 0

(a) The electrical resistance of the wire is determined as 9.27 x 10⁻⁴ ohms.

(b) The current flowing through the wire is 1.1 mA.

<h3>Electrical resistance of the wire</h3>

The electrical resistance of the wire is determined as follows;

ρ = RA/l

RA = ρL

R = ρL/A

Where;

  • A is area of the iron bar
  • ρ is electrical resistivity = 1/conductivity = 1/1.0299 x 10⁷ = 9.7 x 10⁻⁸

A = πd²/4

A =  π x (0.02)²/4

A = 3.14 x 10⁻⁴ m²

R = (9.7 x 10⁻⁸ x 3)/(3.14 x 10⁻⁴)

R = 9.27 x 10⁻⁴ ohms

<h3>From the chart, voltage after 120 minutes ≈ 1.1 V</h3>

Current, I = V/R

where;

  • R = 1 k-ohms = 1000 ohms

I = 1.1/(1000)

I = 1.1 mA

Learn more about resistance here: brainly.com/question/17563681

#SPJ1

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Doubly ionized lithium Li2+ (Z = 3) and triply ionized beryllium Be3+ (Z = 4) each emit a line spectrum. For a certain series of
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Answer:

tex]\lambda_{Be}[/tex] = 22.78 nm

Explanation:

Bohr's model for the hydrogen atom has been used by other atoms with a single electric charge by changing the number of charges by the charge of the new atom (atomic number)

      E_{n}= k e² / 2a₀ (1 /n²)

      ao = h'² / k m e²               h' = h/2πi

For another atom with a single electron in the last layer

      a₀ ’= h’² / k m (Ze)²  

      a₀ ’= a₀ / Z²

Therefore, when replacing in the equation

      E_{n} = - Z²  Eo/n²

     E₀ = 13,606 eV

The transition occurs when the electron stops from one level to another

         E_{n} -  E_{m} = Z² E₀ (1 / n² - 1 / m²) = Z² ΔE

Let's relate this expression to the wavelength

       c = λ f

      E = h f

      E = h c /λ

      h c / λ = Z² ΔE

     λ = 1 / Z² (hc / ΔE)

     λ = 1 / Z² λ_hydrogen

Let's apply this last equation to our case

Lithium Z = 3

     E_{n} = - 9 Eo / n²

     

      40.5 10-9 = 1/9 λ_hydrogen

Beryllium Z = 4

      λ = 1/16 λ_hydrogen

Let's write our two equations is and solve

     40.5 10-9 = 1/9 λ_hydrogen

    tex]\lambda_{Be}[/tex] = 1/ 16 λ_hydrogen

      40.5 10⁻⁹ = 1/9 (16 \lambda_{Be} )

    tex]\lambda_{Be}[/tex] = 40.5 9/16

  tex]\lambda_{Be}[/tex] = 22.78 nm

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Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías

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Answer:

Magnitude of resultant = 131.15

Direction of resultant = 3.97°

Explanation:

||u|| = 70

θ = 40°

\vec{u}_x=||u||cos\theta \\\Rightarrow \vec{u}_x=70cos40=53.62

\vec{u}_y=||u||sin\theta \\\Rightarrow \vec{u}_y=70sin40=44.99

||v|| = 85

θ = 335°

\vec{v}_x=||v||cos\theta \\\Rightarrow \vec{v}_x=85cos335=77.03

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Resultant

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\theta=tan^{-1}\frac{R_y}{R_x}\\\Rightarrow \theta=tan^{-1}\frac{70sin40+85sin335}{70cos40+85cos335}\\\Rightarrow \theta=tan^{-1}0.069=3.97^{\circ}

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A cat jumps off a piano that is 1.3m high. The initial velocity of the cat is 3m/s at an angle of 37degrees above the horizontal
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<em><u>To find how far from the edge of the piano does the cat strike the floor, we need to calculate its time first </u></em>

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Since the <u>time</u> can't be negative the answer is t=0.73

Knowing that we can calculate how far does the cat strike the floor

x=v_{ox}t=3cos(37)(0.73)=1.75m

6 0
3 years ago
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