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2 years ago

Please solve the Problem.

Physics

1 answer:

aalyn [17]2 years ago

5 0

(a) The electrical resistance of the wire is determined as 9.27 x 10⁻⁴ ohms.

(b) The current flowing through the wire is 1.1 mA.

<h3>Electrical resistance of the wire</h3>

The electrical resistance of the wire is determined as follows;

ρ = RA/l

RA = ρL

R = ρL/A

Where;

A is area of the iron bar
ρ is electrical resistivity = 1/conductivity = 1/1.0299 x 10⁷ = 9.7 x 10⁻⁸

A = πd²/4

A = π x (0.02)²/4

A = 3.14 x 10⁻⁴ m²

R = (9.7 x 10⁻⁸ x 3)/(3.14 x 10⁻⁴)

R = 9.27 x 10⁻⁴ ohms

<h3>From the chart, voltage after 120 minutes ≈ 1.1 V</h3>

Current, I = V/R

where;

R = 1 k-ohms = 1000 ohms

I = 1.1/(1000)

I = 1.1 mA

Learn more about resistance here: brainly.com/question/17563681

#SPJ1

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tex]\lambda_{Be}[/tex] = 22.78 nm

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For another atom with a single electron in the last layer

a₀ ’= h’² / k m (Ze)²

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Therefore, when replacing in the equation

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λ = 1 / Z² (hc / ΔE)

λ = 1 / Z² λ_hydrogen

Let's apply this last equation to our case

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40.5 10-9 = 1/9 λ_hydrogen

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λ = 1/16 λ_hydrogen

Let's write our two equations is and solve

40.5 10-9 = 1/9 λ_hydrogen

tex]\lambda_{Be}[/tex] = 1/ 16 λ_hydrogen

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tex]\lambda_{Be}[/tex] = 40.5 9/16

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Answer:

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