A cart travels 4.00 meters east and then4.00 meters north. determine the magnitude ofthe cart’s resultant displacement.
1 answer:
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Answer:
2.31J
Explanation:
the energy for a spring system is given by:
where is the spring constant:
and
is the distance stretched from the equilibrium position.
In the first case
so the energy to stretch the spring 1.81cm is:
and for the second case, the energy to stretch the spring 5.79cm:
so to answer a) we must find the difference between these energies:
Answer:
Total momentum of the system is 378 kg-m/s
Explanation:
It is given that,
Mass of first bumper car, m₁ = 222 kg
Velocity of first bumper car, v₁ = 3.10 m/s (in right)
Mass of other bumper car, m₂ = 165 kg
Velocity of second bumper car, v₂ = -1.88 m/s (in left)
Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :
p = 378 kg-m/s
Hence, the total momentum of the system is 378 kg-m/s