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3 years ago

Using substitution and elimination method solve this simultaneous equation Y=x+1 X+Y=3

Mathematics

1 answer:

Ratling [72]3 years ago

5 0

Answer:

x = 1 and

Y = 2

Step-by-step explanation:

1. Y = x + 1

2. X + Y = 3

Substitute equation 1 into equation 2

X + Y = 3

X + X + 1 = 3

2x + 1 = 3

Subtract 1 from both sides to eliminate 1 on the left side

2x + 1 - 1 = 3 - 1

2x = 2

Divide both sides by 2 to isolate x

2x/2 = 2/2

x = 1

Substitute 1 for x in either equation to get Y

Using equation one, we have

Y = x + 1

= 1 + 1

= 2

x = 1

Y = 2

Check

X + Y = 3

1 + 2 = 3

3 = 3

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4 years ago

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3 years ago

5. Which polynomial is equal to (x5 + 1) divided by (x + 1)?

Mkey [24]

Answer:

B $x^4-x^3+x^2-x+1$

Step-by-step explanation:

Given,

Dividend = $(x^5+1)$

Divisor = $(x+1)$

Step 1: First The dividend is $(x^5+1)$ and Divisor is $(x+1)$ when divided first time the quotient will be $x^4$ and remainder will be $-x^4+1$

Step: 2 Now the new dividend is $-x^4+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3$ and remainder will be $x^3+1$

Step: 3 Now the new dividend is $x^3+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2$ and remainder will be $-x^2+1$

Step: 4 Now the new dividend is $-x^2+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x$ and remainder will be $x+1$

Step: 5 Now the new dividend is $x+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x+1$ and remainder will be 0.

Hence When the polynomial $(x^5+1)$ is divided by $(x+1)$ the answer or quotient will be equal to $x^4-x^3+x^2-x+1$ and remainder will be 0.

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3 years ago