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Pie
2 years ago
15

5. Which polynomial is equal to (x5 + 1) divided by (x + 1)?

Mathematics
1 answer:
Mkey [24]2 years ago
5 0

Answer:

B  x^4-x^3+x^2-x+1

Step-by-step explanation:

Given,

Dividend = (x^5+1)

Divisor = (x+1)

Step 1: First The dividend is (x^5+1) and Divisor is (x+1) when divided first time the quotient will be x^4 and remainder will be -x^4+1

Step: 2 Now the new dividend is -x^4+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3 and remainder will be x^3+1

Step: 3 Now the new dividend is x^3+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2 and remainder will be -x^2+1

Step: 4 Now the new dividend is -x^2+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2-x and remainder will be x+1

Step: 5 Now the new dividend is x+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2-x+1 and remainder will be 0.

Hence When the polynomial (x^5+1) is divided by  (x+1) the answer or quotient will be equal to  x^4-x^3+x^2-x+1 and remainder will be 0.

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Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

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