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valentinak56 [21]
3 years ago
10

there are 36 capenters in a crew. Ona certain day,29 were present .What percent showed up for work?[round to the nearest tenth

Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:


Step-by-step explanation:

We assume, that the number 36 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 100% equals 36, so we can write it down as 100%=36.

4. We know, that x% equals 29 of the output value, so we can write it down as x%=29.

5. Now we have two simple equations:

1) 100%=36

2) x%=29

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

100%/x%=36/29

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.


7. Solution for 29 is what percent of 36


100%/x%=36/29

(100/x)*x=(36/29)*x - we multiply both sides of the equation by x

100=1.24137931034*x - we divide both sides of the equation by (1.24137931034) to get x

100/1.24137931034=x

80.5555555556=x

x=80.5555555556


now we have:

29 is 80.5555555556% of 36 to the nearest tenth is 81%

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A simple random sample of size n equals 200 individuals who are currently employed is asked if they work at home at least once p
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Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

Step-by-step explanation:

<u>step 1:-</u>

Given sample  size n=200

of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week

 Population proportion of employed individuals who work at home at least once per week  P = \frac{x}{n} =\frac{41}{200} =0.205

Q=1-P= 1-0.205 = 0.705

<u>step 2:-</u>

Now  \sqrt{\frac{P Q}{n} } =\sqrt{\frac{(0.205)(0.705)}{200} }

=0.0015

<u>step 3:-</u>

<u>Confidence intervals</u>

<u>using formula</u>

(P  -  Z_∝} \sqrt{\frac{P Q}{n},} (P  +  Z_∝} \sqrt{\frac{P Q}{n},

(0.205-2.58(0.0015),0.205+2.58(0.0015)\\0.20113,0.20887

=0.20113,0.20887[/tex]

<u>conclusion:</u>-

99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

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The conclusion is not correct because

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