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navik [9.2K]
3 years ago
9

What quadratic equation could be solved to find any solutions to the system of equations?

Mathematics
1 answer:
Kipish [7]3 years ago
7 0

Answer:

Step-by-step explanation:

x²+7x-11=-5x+6

x²+7x+5x-11-6=0

x²+12x-17=0

x=\frac{-12\pm \sqrt{12^2-4*1*(-17)} }{2*1} \\=\frac{-12 \pm \sqrt{144+68} }{2} \\=\frac{-12 \pm \sqrt{212}}{2} \\=\frac{-12+2\sqrt{53}}{2}\\=-6 \pm \sqrt{53}

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When factored completely the expression p^4-81 is equivalent to
spayn [35]
   
\displaystyle\\
p^4 - 81 =\\\\
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7 0
3 years ago
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Tcecarenko [31]

Answer:

          /\

\sqrt{20} /     \\sqrt{20}

     /         \

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\sqrt{20}  \     / \sqrt{20}

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Step-by-step explanation:

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3 years ago
A researcher plans to conduct a significance test at the 0.01 significance level. She designs her study to have a power of 0.90
Rasek [7]

Answer: 0.10

Step-by-step explanation: The type 2 error is committed when the alternative hypothesis is rejected when it should have been accepted causing the researcher to accept the null hypothesis which is false.

Power is the probability of avoiding a type 2 error. That is ;

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Given that power = 0.90 ; P(type 2 error) = probability of committing a type 2 error.

P(type 2 error)' = 1 - P(type 2 error) = Probability of not committing or avoiding a type 2 error

0.90 = 1 - P(type 2 error)

P(type 2 error) = 1 - 0.90

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3 years ago
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