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sineoko [7]
3 years ago
12

Consider the exponential function f ( x ) = 13 , 500 ⋅ 0.89^x, which models the value of Mikayla's scooter, where x represents t

he number of years since she purchased the scooter.
What is the value of Mikayla's scooter after 4 years? Explain.
Mathematics
1 answer:
Elden [556K]3 years ago
7 0

Answer: $8470

Step-by-step explanation:

To solve this, you can substitute 4 for x:

f(x) = 13500*.89^4\\f(x) = 13500*0.6274\\f(x) = 8470

Mikayla's scooter is worth around $8470 after 4 years.

It was originally worth 13,500 dollars and depreciated by 11% every year.

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The graph below shows a proportional relationship between yyy and xxx.
Elena-2011 [213]

Answer:

k = 40

Step-by-step explanation:

Given

The attached graph

Required

Calculate the constant of proportionality.

Represent the required constant with k.

Such that:

k = \dfrac{y}{x}

Pick any two corresponding values of x and y

(x,y) = (1,40)

This means that:

x = 1\ and\ y = 40

k = \dfrac{y}{x} becomes

k = \frac{40}{1}

k = 40

8 0
3 years ago
Read 2 more answers
What is the formula to find out percent of discounts?<br>$7.00 IS WHAT PERCENT DISCOUNT OF $25.00?
AleksandrR [38]
Divide the discount by the price
7/25 = 28%
5 0
3 years ago
MATH: EXPONENTIAL WORK PROBLEM 1. HELP PLEASE! 13 pts
Strike441 [17]

The amount of the radioactive substance is 374.6 g

<h3>How to determine the amount of radioactive substance?</h3>

The given parameters are:

  • Initial, a = 424 mg
  • Rate, r = 6%
  • Time, t = 2 hours

The amount of the radioactive substance is calculated as:

A(t) = a(1 - r)^t

This gives

A(t) = 424 * (1 - 6%)^t

At 2 hours, we have:

A(2) = 424 * (1 - 6%)^2

Evaluate

A(2) = 374.6

Hence, the amount of the radioactive substance is 374.6 g

Read more about exponential functions at:

brainly.com/question/2456547

#SPJ1

4 0
2 years ago
Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
___________________________________________________
4 0
3 years ago
How would I figure out a linear equation with two plot points with fractions? (1/3(6),3) and (1/2(19),-2) are my two plot points
murzikaleks [220]

Answer: m=\frac{-30}{79},\ y=5.40

Step-by-step explanation:

Given

Points are \left(6\frac{1}{3},3\right),\ \left(19\frac{1}{2},-2\right)

Convert mixed numeral to fraction

\left(6\frac{1}{3},3\right)\Rightarrow \left(\dfrac{19}{3},3\right)\\\\\left(19\frac{1}{2},-2\right)\Rightarrow \left(\dfrac{39}{2},-2\right)

Slope of the line is

\Rightarrow m=\dfrac{3-(-2)}{\dfrac{19}{3}-\dfrac{39}{2}}\\\\\Rightarrow m=\dfrac{5}{\dfrac{38-117}{6}}\\\\\Rightarrow m=\dfrac{-30}{79}

Equation of line

\Rightarrow \dfrac{y-3}{x-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\text{for y-intercept, put x=0}\\\\\Rightarrow \dfrac{y-3}{0-\dfrac{19}{3}}=\dfrac{-30}{79}\\\\\Rightarrow y-3=\dfrac{190}{79}\\\\\Rightarrow y=3+2.40\\\Rightarrow y=5.40

3 0
3 years ago
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