I believe the answer is x = 1
Answer:
It's located in the third quadrant
(X,Y)
Step-by-step explanation:
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
For this problem you would look at the difference between the two equations. Left and right is determined by the -2 and the +5 in the problems, to get from -2 to +5, you would add 7 but (and i dont really know how to explain the reasoning for this) whenever this number is positive, it goes left and whenever it is negative, it goes right. Figuring out if it shifts up or down is the same, look at the numbers +1 and +9 in the equations. If you go from +1 to +9, you would be adding 8, and this makes it shift upward.
Therefore the answer is the third one: the graph shifts 7 units left and 8 units up
Answer:
-2
Step-by-step explanation:
5+14a=9a-5
+5 +5
10+14a=9a
-9a -9a
10+5a=0
-5a -5a
10= -5a
÷5 ÷5
2= -a
*-1 *-1
-2=a
