Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.
Answer:
4/5
Step-by-step explanation:
Sin is opposite / hypotenuse
Sin x= 16/20
16/20= 4/5
Answer:
2 and 2/3 for the first question
-1/8 for the second one
-1/5 for the third one
ive never done this type of question or maybe it was too long ago for me to remember but out of this answer choices i would guess that its the last one
this is 3
Step-by-step explanation:
you add the numerators which is the top number in order to get 2 and 2/3rds
you subtract 5 from 4 to get -1/8
same situation as the last one, subtract 15 from 11 to make it a negative 4/20 and then simplify that by dividing it by four to get 1/5th
this one i dont understand or remember how to do very well but if i had to guess its the last answer choice
this one you add 3/4 plus 1/4 in order to get 4/4 or rather 1, so basically its asking what 1+1+1 is which is 3
61 is the composite Number your welcome
