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3 years ago

toni bought an old bike for 50$. She fixed it up and sold it for $80. What percent of the original value was toni’s sale price

1 answer:

3 0

For this case what you must do is the following rule of three:
50 ---> 100
80 ----> x
We clear x:
x = (80/50) * (100)
x = 160%
160-100 = 60%
Answer:
toni added 60% of the original value for his sale price

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Identify the k-value that makes the relationship shown in the table below proportional.

uysha [10]

Answer:

The value of k that makes the relationship shown in the table below proportional is $\mathbf{\frac{1}{2}}$

Step-by-step explanation:

The relation is proportional if $y=kx \:or\:k=\frac{y}{x}$

Putting values of x and y to find k.

For x =2 and y =1 k is: $k=\frac{y}{x}=\frac{1}{2}$

For x =4 and y =2 k is: $k=\frac{y}{x}=\frac{2}{4} =\frac{1}{2}$

For x =6 and y = 3 k is: $k=\frac{y}{x}=\frac{3}{6} =\frac{1}{2}$

For x = 8 and y = 4 k is: $k=\frac{y}{x}=\frac{4}{8} =\frac{1}{2}$

For x =10 and y = 5 k is: $k=\frac{y}{x}=\frac{5}{10} =\frac{1}{2}$

So, The value of k that makes the relationship shown in the table below proportional is $\mathbf{\frac{1}{2}}$

5 0

3 years ago

How would I set this up

Aleks [24]

Answer:poop

Step-by-step explanation:

poppo

7 0

3 years ago

Whoever checks my work and tell what I did wrong and the right answer will

gulaghasi [49]

Answer:

See below

Step-by-step explanation:

I believe that you only had to do letters F, H, and J. In that case, let's go over each one!

F: For isolating $d_{1}$ , we need to get rid of the 1/2 first. Let's multiply each side by 2:

$2*m = 2*\frac{1}{2}(d_{1}+ d_{2}) \\2m = d_{1}+ d_{2}$

After this, we just subtract $d_{2}$ from each side to get $d_{1}=2m- d_{2}$ . Dark Blue is correct! Let's now plug in those numbers below:

$d_{1}=2(10)- 13 = 20-13=7$

G: Let's isolate the vw^2 on one side by subtracting y from each side:

$vw^{2} +y-y=x-y\\vw^{2}=x-y$

Let's now divide each side by v, then put each side under a square root to get our final answer:

$\frac{vw^2}{v} = \frac{x-y}{v}\\ w^2 = \frac{x-y}{v}\\\sqrt{w^2} = \sqrt{\frac{x-y}{v}} \\w=\sqrt{\frac{x-y}{v}}$

Orange is correct! Again, let's solve the problem underneath:

w= $w=\sqrt{\frac{38-(-7)}{5}} = \sqrt{\frac{38+7}{5}} = \sqrt{\frac{45}{5}}=\sqrt{9}=3$

H: This one has some stuff that we haven't worked with quite yet (like terms), but our approach is the same: isolate c on one side of the equation.

$2a-2a+3c=17a-2a+21\\3c = 15a+21\\\frac{3c}{3} = \frac{15a+21}{3}\\c = \frac{15a}{3}+ \frac{21}{3} \\c = 5a+7$

Purple is correct! Let's solve the problem:

$c = 5(\frac{16}{5})+7 = 16+7 = 23$

7 0

3 years ago

Please assist me with these problems

Vinil7 [7]

Part (a)

<h3>Answer: y1 and y3 are perpendicular</h3>

This is because the two slopes 2 and -1/2 multiply to -1. Perpendicular slopes multiply to -1 assuming neither line is vertical or horizontal.

=====================================================

Part (b)

Graph each line to see where they cross. The three points of intersection are

(0,4)

(2,-2)

(4,2)

The order of the points doesn't matter.

You could also form three systems of equations pairing up the equations, and solving each system. That way you can find the points of intersection. Graphing may be a better and faster route in my opinion. See the diagram below.

3 0

3 years ago

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Which of the following best describes the relationship between (x+2) and the polynomial 3x^2-x-14

Flauer [41]

One is a linear and the other is a quadratic polynomial.
And (x+2) is indeed a factor.

You can rewrite it as (x+2)(3x-7)

8 0

3 years ago

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