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Reptile [31]
3 years ago
5

What is the solution to the system of equations? Y=2x-5. -8x-4y= -20

Mathematics
1 answer:
stiv31 [10]3 years ago
5 0
<span>Y=2x-5
 -8x-4y= -20
---------------------------
Substitute 2x-5 for y in </span> -8x-4y= -20
<span>-8x-<span>4<span>(<span>2x-5</span>)</span></span></span>=-<span>20
</span>-16x+20=-<span>20
</span>---------------------------------------
Add -20 on each side
<span>-16x+20+-20</span>=-<span>20+-20
</span>-16x = -40
------------------------------------------------
Divide each side by -16
16x / -16 = -40 / -16
x = 5/2 or 2.5
now we have x
===============================================================
To find Y Substitute 2.5 for X in y=<span><span>2x-</span><span>5
y = 2(2.5)-5
y = 0
---------------------------------------
X = 5/2 or 2.5 and Y = 0</span></span>
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Answer: (-5,0)

Step-by-step explanation:

-4x + 5y = 20   the x intercept is when y is zero so input zero into the equation and solve for x.

-4x + 5(0) = 20

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x = -5  

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3 years ago
From a point p on level ground, the angle of elevation of the top of a tree is 60°. If the tree is 39m high, how far is its base
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Hello,

tan 60°=√3
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What is the radius of the cone ? I need help
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pi*r^2

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Megan purchased a new gadget for her technology hobby. She plans to sell it sometime in the future, however, its value depreciat
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Answer:

The second term defines the value that will be depreciated by the rate of 22 units for m months.

Step-by-step explanation:

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The value of the gadget after 'm' months = 2020 - 22m

This expression tells us that, each month Meghan's gadget's price falls by 22 units from the original value.

The original value of the gadget is 2020 units.

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2 years ago
Compute the missing data in the table for the following exponential function f (x) = (one-fourth) Superscript x.
aliina [53]

Answer:

F(4) = \frac {1}{256}

Step-by-step explanation:

Given the following mathematical function;

F(x) = \frac {1}{4^{x}}

<u>When x = 1</u>

F(1) = \frac {1}{4^{1}}

F(1) = \frac {1}{4}

<u>When x = 2</u>

F(2) = \frac {1}{4^{2}}

F(2) = \frac {1}{4*4}

F(2) = \frac {1}{16}

<u>When x = 3</u>

F(3) = \frac {1}{4^{3}}

F(3) = \frac {1}{4*4*4}

F(3) = \frac {1}{4*4*4}

<u>When x = 4</u>

F(4) = \frac {1}{4^{4}}

F(4) = \frac {1}{4*4*4*4}

F(4) = \frac {1}{256}

<u>When x = 5</u>

F(5) = \frac {1}{4^{5}}

F(5) = \frac {1}{4*4*4*4*4}

F(5) = \frac {1}{1024}

8 0
2 years ago
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