In this problem, we're going to explain why any trapezoid that can be inscribed in a circle must be an isosceles trapezoid. In t
his figure, let's assume without loss of generality that segments AB and DC are parallel. By the end of this problem, we want to show that ∠D ≅ ∠C. 1. Explain why ∠A must be supplementary to ∠D.
The single reason for <A and <D being supplementary is the fact that the segment AB is parallel to the segment CD in any trapezoid, so line AD is a transversal with corresponding angles <D and 180-<A congruent which implies <D and <A are supplementary, which answers the question.
Since the trapezoid can be inscribed in a circle, that means angle B + angle D = 180 degree. Since AB is parallel to CD, then angle B + angle C = 180 degree. Therefore, angle D = angle C.
The LCD (least common denominator) is the lowest number that both denominators (12 and 5) go into. The lowest number that both 5 and 12 go into is 60. The LCD of the two fractions is 60.
By counting grid squares, we see the library is 5 miles north and 6 miles east of Ashley's house. Using the Pythagorean theorem, we can find the straight-line distance to be .. d = √(5^2 +6^2) .. = √(25 +36) .. = √61 . . . . . miles .. ≈ 7.81 . . . . miles