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denis23 [38]
3 years ago
12

Find the product. x3(x2+5x+1)

Mathematics
1 answer:
Stella [2.4K]3 years ago
4 0

Answer: x^5+5x^4+x^3


Step-by-step explanation:

assuming the expression is x^3(x^2+5x+1) each term in the bracket is multiplied by x^3

x^3(x^2+5x+1)

=(x^3*x^2)+(x^3*5x)+(x^3*1)

=x5+5x^4+x^3


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Using pythagorean therom whats the answer ??<br> a2 + b2 = c2
swat32
By using Pythagorean Theorem,
C^2= (10)^2+ (9)^2
C^2=100 + 81
C^2=181
C= 13.4cm

Hope it helps!
5 0
3 years ago
Solve the proportion: 11/12.1= x/66 x = <br> A. 64.9 <br> B. 60<br> C. 72.6 <br> D. 55
solmaris [256]

\dfrac{11}{12.1}=\dfrac{x}{66}\qquad\text{cross multiply}\\\\12.1x=(11)(66)\\\\12.1x=726\qquad\text{divide both sides by 12.1}\\\\x=60\\\\Answer:\ B.\ 60

8 0
3 years ago
Read 2 more answers
Hai! What Is 4 Squared???
Nitella [24]

Answer:

16

Step-by-step explanation:

x^{2} = x multiplied by x

so 4^{2} = 16

4 0
2 years ago
Read 2 more answers
10 men and 5 women are meeting in a conference room. Four people are chosen at random from the 15 to form a committee. (a) What
nata0808 [166]

Answer:

Step-by-step explanation:

Given

There are 10 men and 5 women in a conference room

total People=15

(a)Probability that the committee consists of 2 men and 2 women

we have to select from 10 men and 5 women

P=\frac{^5C_2\times ^{10}C_2}{^{15}C_4}

(b)Bob and Jane end up on the same committee

as bob and Jane are necessary to include so there are 4 women and 9 men left to select remaining 2 person

P=\frac{^{13}C_2}{^{15}C_4}

(c)Bob is in the committee but Jane is not

9 men and 4 women left to choose other 3 person

P=\frac{^{13}C_3}{^{15C_4}}

7 0
3 years ago
There are 399 items advertised in a catalog. If the catalog is 75 pages long, what is the average number of items per page?
sukhopar [10]

Answer:

Step-by-step explanation:

Well, we can divide 399 and 75 so it would be 5.32. Round that and it would be about 5 items per page

5 0
2 years ago
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