2 years ago

Which statement is true about an angle?

Mathematics

2 answers:

Varvara68 [4.7K]2 years ago

7 0

They Are all acute, obtuse and right.

Sveta_85 [38]2 years ago

4 0

Where are the statements please?

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3/2 times 2/3 in the simplest form

Lostsunrise [7]

Answer:

3/2 x 2/3 = 1

Step-by-step explanation:

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2 years ago

Find the value of the given variable (-4, r) (-8, 3) m=5

UNO [17]

R=23 because its slope the formula is Y-Y/X-X

6 0

3 years ago

PLEASE HELP ILL GIVE BRAINLY

NISA [10]

Answer:

40.2

Step-by-step explanation:

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3 years ago

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

2 years ago

Help me answer this. Please!!!!!

Maru [420]

1/2*2a= 1a
-6b*1/2=-3b
8* 1/2= 4
so 1a-3b+8

7 0

3 years ago