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3 years ago

Solve for x in the diagram below.

Mathematics

1 answer:

Alika [10]3 years ago

3 0

Answer:

Step-by-step explanation:

x+42=3x

-x -x

42=2x

÷2 ÷2

x=21

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D Z has the greatest measure

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3 years ago

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What is 82 minus 63.9

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Suppose line segment AB has one endpoint at A(0, 0). What are the coordinates of B if (5, 3) is 1/3 of the way from A to B?

prisoha [69]

Answer:

$B(x_2,y_2)= (20,12)$

Step-by-step explanation:

Given

$A = (0,0)$

$Ratio; m : n = 1 : 3$

$Point\ at\ 1 : 3 = (5,3)$

Required

Coordinates of B

This question will be answered using line ratio formula;

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

In this case:

$(x,y) = (5,3)$

$(x_1,y_1) = (0,0)$

$m : n = 1 : 3$

Solving for $(x_2,y_2)$

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$ becomes

$(5,3) = (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})$

$(5,3) = (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})$

$(5,3) = (\frac{x_2}{4},\frac{y_2}{4})$

Comparing the right hand side to the left;

$\frac{x_2}{4} = 5$ -- (1)

$\frac{y_2}{4} = 3$ -- (2)

Solving (1)

$x_2 = 5 * 4$

$x_2 = 20$

Solving (2)

$y_2 = 3 * 4$

$y_2 = 12$

Hence;

$B(x_2,y_2)= (20,12)$

5 0

3 years ago

Help please!! first answer gets marked brainliest!

algol [13]

Answer:

Answer 30

Step-by-step explanation:

if you need to solve or see step- by step explanation here's a link https://mathsolver.microsoft.com/en/solve-problem/%60sqrt%7B%2050%20%20%7D%20%20%20%60times%20%203%20%60sqrt%7B%202%20%20%7D

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2 years ago

Find the domain of the function. (Enter your answer using interval notation.)

Andreas93 [3]

Answer:

$(-\infty,-9)\cup(-9,\infty)$

Step-by-step explanation:

The domain of a rational function is all real numbers <em>except </em>for when the denominator equals 0.

So, to find the domain restrictions, set the denominator to 0 and solve for x.

We have the rational function:

$s(y)=\frac{7y}{y+9}$

Set the denominator to 0:

$y+9=0$

Subtract 9:

$y\neq-9$

So, the domain is all real numbers except for -9.

In other words, our domain is all values to the left of negative 9 and to the right of negative 9.

In interval notation, this is:

$(-\infty,-9)\cup(-9,\infty)$

And we're done :)

4 0

3 years ago