All categories

3 years ago

Help me with 9, 10, 11, 12, 13 & 14 please!!

Mathematics

2 answers:

Mrac [35]3 years ago

7 0

9 cars

13.25$

22.7 miles

It weighs .01 kilograms and 1000 milligrams

4 classes

29,889 Ft 9963 yds

vagabundo [1.1K]3 years ago

5 0

9) 42/5= 8.4 but you can't have part of a car so round up to get 9 cars
10) 39.75/3= $13.25 per pair
11) 500/22=22.72 repeating, I would say an average of 23 mile per gallon
12) Kilograms- 0.01 and milligrams- 10,000
13) 112/35= 3.2 or 4
14)162 times 210= 34020 and 51 times 81= 4131
34,020-4,121= 29,889 ft and 3,321 yds

I really hope that I helped you!!!

You might be interested in

What is the next term in the sequence

Nesterboy [21]

Answer:

-5/2

Step-by-step explanation:

The next term will be,

→ -2/4

→ (-2-3)/(4÷2)

→ -5/2

Hence, the solution is -5/2.

8 0

2 years ago

Read 2 more answers

Suppose account numbers for an internet service provider consist of alpha-numeric characters. The first character is a digit (0

Amiraneli [1.4K]

Answer:

20,442,240 account numbers are possible.

Step-by-step explanation:

The first character has 10 possible values.

The next 2 has 26 * 26 = 676 possible combinations.

The last 4 has 9*8*7*6 = 3024 possible combinations.

So the answer is 10 * 676 * 3024

= 20,442,240.

6 0

2 years ago

A rectangular garden has a width of five times an unknown variable x plus two. The length is one more than three times the same

wolverine [178]

Answer: just saying I’m pretty sure it’s 36... don’t put it cause I’m not 100% sure it’s right?

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (

Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

$\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408$

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0

2 years ago

Pls hellpp! urgentt! please

Masja [62]

Answer:

Step-by-step explanation:

Perimeter of Square = 40 cm

4*side = 40

side = 40/4

side = 10 cm

Area of shaded region= Area of square - [Area of triangle 1 + Area of triangle 2]

$=[side*side]-[\frac{1}{2}*b*h+\frac{1}{2}*b*h]\\\\=[10*10]-[\frac{1}2}*3*10+\frac{1}{2}*10*6]\\\\=100-[3*5+5*6]\\\\=100-[15+30]\\\\=100-45\\\\=55cm^{2}\\$

Percentage = (55/100)*100=55%

6 0

3 years ago