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3 years ago

The integer -3 would BEST represent which of these events?

Mathematics

2 answers:

nevsk [136]3 years ago

6 0

Lll only because one and two you add on two hours. However for three you use (and therefore lost) 3 gallons

natulia [17]3 years ago

3 0

III only is the answer I believe.

You might be interested in

Work your brain today y'all!! I had $3.00. My Mom gave me $10.00. My Dad Gave me $30.00. My Aunt & Uncle gave me $100.00. I

Citrus2011 [14]

Hey there! I'm happy to help!

We start out with 3.

Our mom gives us 10.

3+10=13

Our dad gives us 30.

13+30=43

Our aunt and uncle give us 100.

43+100=143

And we have another 7.

143+7=150

Therefore, we have $150 now.

Have a wonderful day! :D

6 0

2 years ago

Read 2 more answers

Convert 95 pints to gallons. Round to one decimal place.

Serggg [28]

11.9 gallons. Hope I helped!

8 0

3 years ago

A grocer has two kinds of tea: one selling for 80 cents a pound and the other selling for 60 cents a pound. How many pounds of e

goblinko [34]

Answer:

35 pounds of tea for 80 cents.

Step-by-step explanation:

Equation::

value + value = value

80x + 60(50-x) = 74*50

80x + 60*50 - 60x = 74*50

20x = 14*50

x = 35 lbs (amt. of 80 cent tea to use)

50-x = 15 lbs (amt. of 60 cent tean to use)

4 0

2 years ago

Read 2 more answers

Maya is the manager for the track team. She created a table to compare finish times from the second practice to the first

Oksi-84 [34.3K]

Answer:

Runners that decrease times are not improving

Step-by-step explanation:

4 0

3 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago