Answer:
Step-by-step explanation:
let it's breadth be x
area of rectabgle=l*b
259=18.5*b
259/18.5=b
14=b
perimeter of rectangle=2(l+b)
=2(18.5+14)
=2*32.5
=65 cm
The answer that you said is right. I totally agree with you.
Solution :
Faulty electrical connects = P(A) = 0.80
Mechanical defects = P(B) = 0.92
Mechanical defects are related to loose keys = P(C/B) = 0.27
Improper assembly = P(D/B) = 0.73
Defective wires = P(E/A) = 0.35
Improper connections = P(F/A) = 0.13
Poorly welded wires = P(G/A) = 0.52
Now, the probability due to loose keys = 0.27 x 0.92 = 0.2484
Improperly connected = 0.13 x 0.80 = 0.1040
Poorly welded wires = 0.52 x 0.80 = 0.4160
So, the probability that a failure is due to improperly connected or poorly welded wires = 0.1040 + 0.4160
= 0.5200
0.0003 would be 1/10 of 0.00003. If you divided 0.00003 by 10 you would get 0.0003. In fraction form it is 3/10,000
Hoped this helped.
It is fore multiple things. if thats your quiestion. y can =4 and x=0, or x can = 2 and y=0.
