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Pachacha [2.7K]
3 years ago
13

Find an equation of the line that

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer:

y = (-11/12)x - 3

Step-by-step explanation:

Recall that for a linear equation in the form y = mx + b,

m = slope and b = y-intercept.

hence to satisfy parts (a) and (b) of the questions, we need to extract the y-intercept from the equation in part (a) and the slope from part (b)

For part (a)

given: y+7x+3=0  (rearrange this to get slope-intercept form)

y+7x+3=0 (subtract 3 from both sides)

y + 7x = -3  (subtract 7x from both sides)

y = -7x - 3

we can see that the y-intercept is -3.

For part (b)

given: -11x -12y=-7  (rearrange this to get slope-intercept form)

-11x -12y=-7  (add 11x toboth sides)

-12y = 11x - 7  (divide both sides by -12)

y = (-11/12) - (7/12)

we can see that the slope is (-11/12).

combining the y-intercept from part (a) and the slope from part (b) into the general equation given in the first line above,

y = (-11/12)x - 3 (answer)

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The equation of the perpendicular bisector of BC with B(-2, 1), and C(4, 2) is y = 7.6 - 6•x

<h3>Which method can be used to find the equation of the perpendicular bisector?</h3>

The slope, <em>m</em>, of the line BC is calculated as follows;

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The slope of the perpendicular line to BC is -1/(1/6) = -6

The midpoint of the line BC is found as follows;

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The perpendicular bisector is the perpendicular line constructed from the midpoint of BC.

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Learn more about equations of perpendicular lines here:

brainly.com/question/11635157

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