Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.
Answer:-11
Step-by-step explanation:
Answer:
See below for answer.
Step-by-step explanation:
m ∠3 = m∠ 7 If ║ then cor. ∠s are =
m ∠2 = m∠7 Transitive ∠2 = ∠3; ∠3 = ∠7; ∴∠2 = ∠7
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