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Pie
3 years ago
12

Can you tell me what are ratio

Mathematics
1 answer:
irina [24]3 years ago
7 0
A ratio is a comparison in sizes. Like if i have 10 grams of sand, 7 are yellow and 3 are blue. That is a 7:3 ratio. A comparison in size.
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a trail mix recipe is 15% raisins. if Tom wants to make 20 cups of trail mix, what amount of raisins will he need?
Airida [17]

Answer: Tom will need 3 cups of raisins

Step-by-step explanation:

8 0
3 years ago
Please help last question
Len [333]

Answer:

A 5% possibility.

Step-by-step explanation:

Find all of the totals:

total male = 4+6+2+2=14

total female = 3+4+6+3=16

freshman = 4+3=7

sophomore = 6+4=10

Junior = 2+6=8

Senior = 2+3 = 5

total overall= 5+8+10+7+16+14=60

Female seniors are = 3

So 3/60 = 0.05=5%

6 0
3 years ago
A recent article reported that a job awaits only one in three new college graduates. The major reasons given were an overabundan
nikitadnepr [17]

Answer:

z=\frac{0.4 -0.33}{\sqrt{\frac{0.33(1-0.33)}{200}}}=2.105  

p_v =P(z>2.105)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of students that had job at the school mentioned is not significantly higher then 0.33 .  

Step-by-step explanation:

1) Data given and notation  

n=200 represent the random sample taken

X=80 represent the number of students that had jobs

\hat p=\frac{80}{200}=0.4 estimated proportion of students that had jobs

p_o=0.3333 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of students that have jobs at the school mentioned is higher than the reported value at the article:  

Null hypothesis: p\leq 0.33  

Alternative hypothesis:p > 0.33  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.33}{\sqrt{\frac{0.33(1-0.33)}{200}}}=2.105  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.105)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of students that had job at the school mentioned is not significantly higher then 0.33 .  

7 0
3 years ago
Help me please
Goshia [24]
Midpoint is (-2 , -0.5)
6 0
3 years ago
Algebraically solve the system of equations shown below. Note that you can use either factoring or the quadratic formula to find
ivann1987 [24]
6x^2+19x-15=-12x+15\\
6x^2+31x-30=0\\
6x^2+36x-5x-30=0\\
6x(x+6)-5(x+6)=0\\
(6x-5)(x+6)=0\\
x=\frac{5}{6} \vee x=-6\\\\
y=-12\cdot\frac{5}{6} +15\vee y=-12\cdot(-6)+15\\
y=-10 +15\vee y=72+15\\
y=5 \vee y=87\\\\
x=\frac{5}{6} \wedge y=5\\
x=-6 \wedge y=87
7 0
3 years ago
Read 2 more answers
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