Answer:
Step-by-step explanation:
Given that there is a function of x,
Let us find first and second derivative for f(x)
When f'(x) =0 we have tanx = 1 and hence
a) f'(x) >0 for I and III quadrant
Hence increasing in 
and decreasing in 
Hence f has a maxima at x = pi/4 and minima at x = 3pi/4
b) Maximum value = 
Minimum value = 
c)
f"(x) =0 gives tanx =-1
are points of inflection.
concave up in (3pi/4,7pi/4)
and concave down in (0,3pi/4)U(7pi/4,2pi)
Answer:
He practicably stole her money
Step-by-step explanation:
that scu m bag
Answer: -3
Step-by-step explanation:
Answer:
the answer is option E.
Step-by-step explanation:
it is in the form f/g (x).
we know f and g from the equation;
we can rewrite it as, (√(9-x^2)/(3x-1))
if you notice you cannot put any number less than -3 or greater than 3 in the numeror because if you do you get a negative root which is false. for instance if you put 4 or -4 in the numerator you get 9 - (4 or -4 square ) which is 9- 16 which is a negative number and you cannot take root of a negative number.
on the numerator if you put 1/3 as the value for x you will get zero in the denominator. and any number divided by zero is undefined so that cannot be.
this means that option E is the right one that satisfies the condition. it means the domain is [-3, 1/3) U (1/3, 3] .
