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otez555 [7]
3 years ago
12

Circle the quadrilateral that does not belong with the other three. Explain your reasoning please help me this is due tomorrow

Mathematics
1 answer:
jeka943 years ago
3 0
Trapezoid because it doesn't have to parareles sides like the other
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Anyone have any idea what the answer could be?
DaniilM [7]

Answer:

y = -1/4x -1

Step-by-step explanation:

Mathematically, we have the slope intercept form as;

y = mx + b

where m is the slope and b is the y-intercept

from the question;

m is -1/4

So we have :

y = -1/4x + b

To get the value of b, we substitute the coordinates given and solve for b

Firstly, multiply through by 4

That will

give ;

4y = -x + 4b

4(-4) = -12 + 4b

-16 = -12 + 4b

-16 + 12 = 4b

4b = -4

b = -4/4

b = -1

So the equation in the slope intercept form is;

y = -1/4x -1

5 0
3 years ago
What is the queuing theory and how to use it?
ziro4ka [17]

Answer:

As a branch of operations research, queuing theory can help inform business decisions on how to build more efficient and cost-effective workflow systems. Queuing theory is the study of the movement of people, objects, or information through a line.

8 0
2 years ago
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Which of the following is a situation in which an equation cannot be solved
Klio2033 [76]

Answer:

B One term of the polynomial has a degree of 3

3 0
3 years ago
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What 3 numbers can be multiplied together to get 180?
hichkok12 [17]

2×6×15=180

Step-by-step explanation:

2×6=12

12×15=180

4 0
3 years ago
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Linear Algebra: Permutation Matrices Let M be the matrix {{0,0,0,1,0}, {0,0,1,0,0}, {0,1,0,0,0}, {0,0,0,0,1}{1,0,0,0,0}}. What i
FromTheMoon [43]

Multiplying M by any matrix A would return new matrix, B, in which

• the 1st row of B is equal to the 4th row of A,

• the 2nd row of B is equal to the 3rd row of A,

• the 3rd row of B is equal to the 2nd row of A,

• the 4th row of B is equal to the 5th row of A, and

• the 5th row of B is equal to the 1st row of A.

The pattern here is

1 => 4 => 5 => 1

2 => 3 => 2

Let {4, 3, 2, 5, 1} denote the matrix M, where each number refers to the row of the identity matrix, I.

Using this notation, the pattern above gives

M² = {5, 2, 3, 1, 4}

M³ = {1, 3, 2, 4, 5}

M⁴ = {4, 2, 3, 5, 1}

M⁵ = {5, 3, 2, 1, 4}

M⁶ = {1, 2, 3, 4, 5}

so that <em>n</em> = 6.

(Notice that the first cycle has length 3 and the second one has length 2; the minimum <em>n</em> needed here is then LCM(2, 3) = 6.)

6 0
3 years ago
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