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fgiga [73]
3 years ago
8

So confused need help. If u have a easy way to solve please help

Mathematics
1 answer:
ycow [4]3 years ago
3 0

Answer: X= 6-4^z/2

Step-by-step explanation: first you need to get rid of the 4. You subtract it from both sides. So now

2x=6-4 to the power of z

So now you need to get rid of the 2. You divide both sides by two. Then you get

X= 6-4^z/2

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19. 9a2b = c + 4a, for a
xenn [34]

Answer:x/5 + 2b/5

Step-by-step explanation:

9a-2b=c+4a solve for a

9a-2b=c+4a

add -4a to both sides

9a-4a-2b=x+4a-4a

5a-2b=x

add 2b to both sides

5a-2b+2b=x+2b

5a= x+2b

divide by 5

5a/5 = x/5 +2b/5

a= x/5 + 2b/5

5 0
1 year ago
The grades on a physics midterm at Covington are roughly symmetric with = 72 and = 2.0. Stephanie scored 74 on the exam. Find th
Aleksandr [31]

Answer:1.00

Step-by-step explanation:

A=74-72/2.0

And I did it on kahn

4 0
3 years ago
Read 2 more answers
The angle which is less than 90 degrees is called?
BlackZzzverrR [31]

Answer:

An acute angle is an angle less than 90°

5 0
2 years ago
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The graph of g(x) is a reflection and translation of ∛x see attachment, please help
svetoff [14.1K]
<h2>Hello!</h2>

The answer is: g(x)=-\sqrt[3]{x-1}

<h2>Why?</h2>

Let's check the roots and the shown point in the graphic (2,-1)

First,

0=-\sqrt[3]{x-1}\\\\0^{3}=(-\sqrt[3]{x-1})^{3}\\\\0=-(x-1)\\\\x=1

then,

g(0)=-\sqrt[3]{0-1}\\g(0)=-(-1)\\g(0)=1\\y=1

So,  we know that the function intercepts the axis at (1,0) and (0,1), meaning that the function match with the last given option

(g(x)=-\sqrt[3]{x-1})

Second,

Evaluating the function at (2,-1)

y=-\sqrt[3]{x-1}\\-1=-\sqrt[3]{2-1}\\-1=-\sqrt[3]{1}\\-1=-(1)\\-1=-1

-1=-1

It means that the function passes through the given point.

Hence,

The equation which represents g(x) is g(x)=-\sqrt[3]{x-1}

Have a nice day!

5 0
2 years ago
I have 12 coins x of them are R5 coins and the rest are R1 coins. An expression in the in terms of x for the number of R1 coins
Marrrta [24]

Answer:

ans= 12-x=r1 coin...

Step-by-step explanation:

hope u can do..

7 0
3 years ago
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