According to a survey, 25% of students at a particular school take the bus to school. A total of 200 students take the bus. How
1 answer:
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Answer:
Step-by-step explanation:
Quiana has 5 times more text messages from Yolanda than from Pierre, we also know that she actually has 30 text messages from Yolanda. In other words, 30 texts from Yolanda is 5 times more text messages than from Pierre.
Thus, if we call p the number of texts messages from Pierre we would have that
(since 30 texts from Yolanda is 5 times more than p, we can divide by 5 to find p)
And if we solve this equation we would get that Quiana has 6 text messages from Pierre
Answer:
Step-by-step explanation:
STEP 1:
2/3 + 7/10 = ?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(2/3, 7/10) = 30
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
*
+
= ?
Complete the multiplication and the equation becomes
The two fractions now have like denominators so you can add the numerators.
Then:
This fraction cannot be reduced.
The fraction 41/30
is the same as
41 divided by 30
Convert to a mixed number using
long division for 41 ÷ 30 = 1R11, so
41/30 = 1 11/30
Therefore:
2/3+7/10= 1 11/30
STEP 2:
41/30 + -2/3
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(41/30, -2/3) = 30
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
The two fractions now have like denominators so you can add the numerators.
Then:
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using
GCF(21,30) = 3
Therefore:
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Answer:
<h2>Step-by-step explanation: