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olasank [31]
3 years ago
15

Can someone help me with 27 and 28?

Mathematics
1 answer:
netineya [11]3 years ago
8 0

<u>You have to do: {</u><u><em> x^4 * 6x^2 </em></u><u>}</u>

(^ means to the power of)

(* means multiply)

Answer in picture

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Darya [45]
The answer would be 48 because the first answer is 60 minus the second answer which is 12 to get 48
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3 years ago
(4m-2) (m2 + 5m - 6)please fast​
Masteriza [31]

Answer:

4m3+18m2−34m+12

Step-by-step explanation:

=(4m+−2)(m2+5m+−6)

=(4m)(m2)+(4m)(5m)+(4m)(−6)+(−2)(m2)+(−2)(5m)+(−2)(−6)

=4m3+20m2−24m−2m2−10m+12

3 0
3 years ago
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Find the equation of the line that is perpendicular to y = – 1 4 x – 8 and passes though the point (2, –4).
vivado [14]

The equation of the line is y=\frac{1}{4}x-\frac{29}{7}

Explanation:

The equation of the line is perpendicular to y=-14 x-8

The equation is of the form y=mx+b where m=-14

<u>Slope:</u>

The slope of the perpendicular line can be determined using the formula,

m_1 \cdot m_2=-1

-14 \cdot m_2=-1

       m_2=\frac{1}{14}

Thus, the slope of the line is m=\frac{1}{14}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the slope m=\frac{1}{14} and the point (2,-4), we get,

y+4=\frac{1}{14}(x-2)

Simplifying, we get,

y+4=\frac{1}{14}x-\frac{1}{7}

     y=\frac{1}{14}x-\frac{1}{7}-4

     y=\frac{1}{4}x-\frac{29}{7}

Thus, the equation of the line is y=\frac{1}{4}x-\frac{29}{7}

3 0
4 years ago
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iren [92.7K]
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3 years ago
What is 0.02349 written in standard form to 3 significant figures
Alinara [238K]

Answer: The answer is (B)

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5 0
3 years ago
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