X
−
2
>
0
x
-
2
>
0
|
−
3
+
2
−
4
|
|
-
3
+
2
-
4
|
csc
2
(
x
)
−
cot
2
(
x
)
csc
2
(
x
)
-
cot
2
(
x
)
Since Joe has 5/6 pounds left and he only needs 1/3 pounds
each day to feed the birds, therefore the number of remaining day’s worth of
seed is:
days = (5/6) / (1/3) = 2.5
The remaining seed can run up to 2 and half days. This also
means that after 2 days, he is remained with ½ of 1/3 pound. ½ of 1/3 pound is
equivalent to 1/6 pound. Therefore the correct rectangle model to use is:
<span>Rectangle
model divided into 3 equal sections, two sections are labeled one-third and one
section is labeled one-sixth, equaling two and one-half days.</span>
The value of any log function approaches negative infinity as the argument approaches zero from above.
The correct answer would be 128.
(x-3)^2 + (y+5)^2 = 25
remove the ^2's from the left side:
(x-3) +(y+5) = sqrt(25)
(x-3) +(y+5) = 5
radius = 5
now solve for zero 's on the left side:
x-3 = 0 x = 3 (3-3=0)
y+5 = 0 y = -5 (-5 +5=0)
so center = (3,-5) and radius is 5
Answer is last one.
