You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²
At the same time, a truck moving speed o 8.50 m/s passes the car
D=v.t (for the truck)
And d= v.t+1/2.a.t²(for the car)
v.t=1/2.a.t²
t=2.v/a
t=2.8.50 m/s/ 2.70 m/s²
17m/2.70=6.29
This mean that the distance is
D=v.t=8.50m/s.6.29= 53.465 m/s
The speed of the car is
Vcar=a.t
2.7m/s2×× 53.65
=144.34
Answer:
x > 8
Step-by-step explanation:
Solve for x to find the solution.
10 - 4x < -22
Subtract 10 from both sides.
-4x < -32
Divide both sides by -4. Flip the sign when dividing by negative.
x > 8.
Answer: 9 gallons
<u>Step-by-step explanation:</u>
Set up the proportion, then multiply to solve for the variable.
9 gallons = x