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3 years ago

Which is the coefficient in the algebraic expression 12x + z^4 ?

Mathematics

2 answers:

love history [14]3 years ago

8 0

I think the coefficient is the 12, before the variable

Phantasy [73]3 years ago

7 0

Remember a coefficient is any number that comes before a variable as a multiplicative. So, in the equation 12x+z^4 our coefficient would be 12.

Hope this helps!

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Tju [1.3M]

Answer:

The given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Step-by-step explanation:

Here, the given expression is: $(\frac{5}{6} a^{9}p^{5}) ^{3}$

Now, starting from the outer most bracket.

As we know :

$(abc)^{n} = (a)^{n} \times (b)^{n} \times (c)^{n}$

and $(a^m)^{n} = a^{(m \times n)}$

⇒ $(\frac{5}{6} a^{9}p^{5}) ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3} \times (p^{5}) ^{3}\\$

$=\frac{125}{216} \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Hence, the given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

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rodikova [14]

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zhenek [66]

Answer:

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Step-by-step explanation:

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