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Svetlanka [38]
3 years ago
12

Which is the coefficient in the algebraic expression 12x + z^4 ?

Mathematics
2 answers:
love history [14]3 years ago
8 0
I think the coefficient is the 12, before the variable 
Phantasy [73]3 years ago
7 0
Remember a coefficient is any number that comes before a variable as a multiplicative. So, in the equation 12x+z^4 our coefficient would be 12.

Hope this helps!

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Find the area of a circle if the diameter is 13
horrorfan [7]


A=pi times radius times radius

13 divided by 2 equals to 6.5

A=3.14 times 6.5 times 6.5

A=132.665

hope it helps

Can you choose mine as the brainliest answer

4 0
3 years ago
-4.8=1.2s+2s+4<br><br><br>Please help me <br>​
nikdorinn [45]
Simplify both sides of the equation
-4.8=1.2s+2s+4
Combine like terms
-4.8=(1.2s+2s)+(4)
-4.8=3.2s+4
Flip the equation
3.2s+4=-4.8
Subtract both sides by 4
3.2s+4-4=-4.8-4
3.2s=-8.8
Divide both sides by 3.2
3.2s/3.2= -8.8/3.2
S=-2.75 will be the answer hope it helps
6 0
3 years ago
On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
Otrada [13]

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

5 0
3 years ago
Read 2 more answers
What’s the radius of this button ?
Neporo4naja [7]

Answer:

2.5 cm

Step-by-step explanation:

We see the diameter is 5cm

so the radius is half the diameter

5/2 = 2.5 cm

3 0
3 years ago
Read 2 more answers
Help behjrbjhvbjfjdji
Olegator [25]
The answer is 24 rides! I hope this helps!
3 0
3 years ago
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