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son4ous [18]
3 years ago
10

The aurora is caused when electrons and protons, moving in the earth's magnetic field of ≈5×10−5 T, collide with molecules of th

e atmosphere and cause them to glow. What is the radius of the circular orbit for (a) an electron with speed 1.0×106m/s and (b) a proton with speed 7.0×104m/s. What is re in meters and what is rp in meters?
Chemistry
2 answers:
kvasek [131]3 years ago
7 0

Answer:

a) 0.114 meters is the radius of the circular orbit for an electron with given speed.

b) 14.6 meters is the radius of the circular orbit for a proton with given speed.

Explanation:

Force on the charge particle :

F = qvB

Since, the particle is revolving around in a circular path ;

F'=\frac{mv^2}{r}

particle in constantly moving in circular path under action of magnetic field:

F = F'

qvB=\frac{mv^2}{r}

r=\frac{mv}{qB}

Where :

r = radius of the circular path

m = mass of the particle

v = velocity of the particle

B = magnetic field

q = magnitude of  charge on the particle

a)  Velocity of the electron =  v=1.0\times 10^6 m/s

Mass of electron = m = 9.11\times 10^{-31} kg

Charge on an electron , q= 1.602\times 10^{-19} C

B = 5\times 10^{-5} T

Radius of the circular orbit for an electron with given speed =r_e

r_e=\frac{9.11\times 10^{-31} kg\times 1.0\times 10^6 m/s}{1.602\times 10^{-19} C\times 5\times 10^{-5} T}

r_e = 0.114 m

0.114 meters is the radius of the circular orbit for an electron with given speed.

b)  Velocity of the proton =  v=7.0\times 10^4 m/s

Mass of electron = m = 1.67\times 10^{-27} kg

Charge on an electron , q= 1.602\times 10^{-19} C

B = 5\times 10^{-5} T

Radius of the circular orbit for a proton with given speed =r_p

r_e=\frac{1.67\times 10^{-27} kg\times 7.0\times 10^4 m/s}{1.602\times 10^{-19} C\times 5\times 10^{-5} T}

r_p = 14.6 m

14.6 meters is the radius of the circular orbit for a proton with given speed.

borishaifa [10]3 years ago
5 0
The correct answer to this question is

You can use this equation.
f = m v^2 / r
f = q B v 

<span>r = m v^2 / q B v = m v / q B = </span>

<span>(a) an electron 9.109×10^-31 * 4.0×10^6 m/s / 1.602×10^-19 * 5.5*10^-5 T = 0.4135 m </span>
(b) a proton 1.673×10^-27 * 7.0×10^4 m/s ./ 1.602×10^-19 * 5.5×10^-5 T = 13.29 m
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