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3 years ago

If you had 20,000 litres of NO2 how many moles would you have

Chemistry

1 answer:

vova2212 [387]3 years ago

6 0

Answer:

The correct answer is 0.89 mol.

Explanation:

At STP (Standard Temperature and Pressure) conditions, 1 mol of an ideal gas occupies a volume of 22.4 L. If we assume STP conditions, we can consider a convertion factor of 1 mol/22.4 L to convert the volume of NO₂ from liters to moles:

20,00 L x 1 mol/22.4 L = 0.89 mol

So, at STP, we would have 0.89 mol of NO₂

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Anton [14]

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3 years ago

What is the overall charge of the electron cloud of the atom? Explain.

Tresset [83]

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3 years ago

the specific heat of iron is 0.4494 j/g°C. how much heat energy (kj) is transferred when a 24.7 kg iron ingot is cooled from 880

guapka [62]

Answer is: 9623.85 kJ of heat is <span>transferred from iron ingot.
</span>m(Fe) = 24.7 kg · 1000 g/kg = 24700 g; mass of iron ingot.
C = 0.4494 J/g°C; t<span>he specific heat of iron
</span>ΔT = 880°C - 13°C; temperature <span>difference.</span>
ΔT = 867°C.
Q = m·C·ΔT.
Q = 24700 g · 0.4494 J/g°C ·867°C.
Q = 9623856.06 J ÷ 1000J/kJ.
Q = 9623.85 kJ.

8 0

4 years ago

The<br>volume<br>occupied by 5.0g in neon<br>03368 atm and<br>a temperatureof <br>35°C will be?

olga55 [171]

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4 0

3 years ago

2NaClO3 ——> 2NaCl + 3O2

Alborosie

Answer:

<h3>1) 208.09 g</h3><h3>2) 7.11 × 10²² particles</h3>

<h2>Explanation:</h2><h3>NUMBER ONE</h3>

<u>Find moles of Known Substance (NaCl)</u>

Moles of NaCl = mass ÷ molar mass

= 114.25 g ÷ 58.44 g/mol

= 1.955 mol

<u>Use Mole Ratio of Known to Unknown (NaCl : NaClO₃) to Determine Moles of Unknown</u>

The mole ratio of NaCl to NaClO₃ is 2 to 2 or simply 1 to 1.

This means that for each mole of NaCl produced the same number of moles of NaClO₃ was decomposed.

∴ since moles of NaCl = 1.955 mol,

then moles of NaClO₃ = 1.955 mol

<u>Find Mass of Unknown </u>

Mass of NaClO₃ = moles × molar mass

= 1.955 mol × 106.44 g/mol

= 208.09 g

<h3>NUMBER TWO</h3>

<u>Determine the Moles of Known (O₂)</u>

moles of O₂ = (volume × density) ÷ molar mass

= (68.30 L × 0.0828 g/L) ÷ 32 g/mol

= 0.177 mol

<u>Use Mole Ratio of Known to Unknown (O₂ : NaClO₃) to Determine Moles of Unknown</u>

Mole ratio of O₂ : NaClO₃ is 3 : 2. Therefore for each mole of oxygen produced, ²/₃ the moles of NaClO₃ is produced.

∴ if moles of O₂ = 0.177 mol

then moles of NaClO₃ = 0.177 mol × ²/₃

= 0.118 mol

<u>Find the Number of Particles of Unknown</u>

Number of particles = moles × Avogadro's Number

= 0.118 mol × (6.022 × 10²³ particles/mol)

= 7.11 × 10²² particles

3 0

3 years ago