Question

A child looks up in front of himself and sees a hot air balloon in the sky. The angle of elevation from the child to the balloon is 52. The distance from the child to the spot of the ground directly under the balloon is 75 ft. How high is the balloon? (Disregard the distance from the ground to the child’s eyes.)

Answer 1

Answer: 95.996 feet ( Approx )

Step-by-step explanation:

Here, the distance of the child from the spot that is directly under the balloon = 75 ft

Let the distance of the balloon from the ground = h ft

Now, According to the question,

We can write,

$\frac{\text{ The distance of the balloon from the ground}}{\text{ The distance of the child from the spot that is under balloon}}=tan52^{\circ}$

$\frac{h}{75}=tan52^{\circ}$

$h = tan52^{\circ}\times 75=95.9956224145\approx 95.996\text{ feet}$