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True [87]
3 years ago
15

Emma has already read 12 of 29 books on her summer reading list. What percent of the books on her list has she read already?

Mathematics
2 answers:
BaLLatris [955]3 years ago
4 0
41 % of the books have been read
leonid [27]3 years ago
3 0
You divide 12/29 and that gives you 0.4137 which equals 41 percent
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HELP ASAP
boyakko [2]

Answer:

Linear would be fine as it doesn't decrease to under zero

and a curve graph would represent this data fine at 10818 turning point.

Step-by-step explanation:

6 0
3 years ago
How do you solve rational expressions
Stells [14]

Answer:

lots of multiplying I've noticed

5 0
3 years ago
Read 2 more answers
How to solve this?? (-4)-(-8)+(-4)
kirill115 [55]
(-4) - (- 8) + (- 4)
- 4 - (- 8) + (- 4)
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= 0
6 0
2 years ago
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Tickets to a school basketball game cost $4 for students and $7 for adults. At the end of the night, 168 tickets are sold for a
stepan [7]
4s+7a=861
s+a=168

This can be solved using either elimination or substitution. I am going to use substitution.

Solve s+a=168 for s
s=168-a

Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861

Solve for a
672+3a=861
3a=189
a=63

Substitute 63 for a in s=168-a
s=168-63=105

So, s=105 student tickets and a=63 adult tickets
3 0
3 years ago
Can someone explain how to do "interquartile range"
Andrews [41]

What is it?

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

How do you find IQR?

<em>Step 1: Put the numbers in order. ...</em>

<em>Step 2: Find the median. ...</em>

<em>Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...</em>

<em>Step 4: Find Q1 and Q3. ...</em>

<em>Step 5: Subtract Q1 from Q3 to find the interquartile range.</em>

7 0
2 years ago
Read 2 more answers
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