The concert director can choose the new members by holding try outs to take the the possible candidate’s skills, performance and professionalism into consideration to be a part of the large show. Another way is by voting amongst other people in their school to see who the audience would be excited to see preforming in the show.
Answer:
Angle A is 29 degress Angle B is 61 Angle C is 90
Side AB is 5.8 Side BC is 2.8 and Side AC is 5.1
Step-by-step explanation:
Angle A is found using triangle interior theorem.
I found side AC by using law of sines
b/sin b= c/sin c
x/sin 61= 5.8/sin 90( which equal 1)
x=5.1
I found side BC by using pythagoren theorem.
a^2 + b^2=c^2
5.1^2+ b^2=5.8^2
26.01+b^2=36.64
b^2=7.63
b=approx 2.8.
Hey there!
39 = - u / 6
MULTIPLY 6 to BOTH SIDES
39(9) = (-u / 6)(6)
CANCEL out: the RIGHT side
KEEP: the LEFT side because it helps solve for the u-value
NEW EQUATION: -u = 234
DIVIDE -1 to BOTH SIDES
-1u / -1 = 234 / -1
CANCEL out: -1 / -1 because it gives you 1
KEEP: 234 / -1 because it gives you the result of the u-value
NEW EQUATION: u = 234 / -1
SIMPLIFY IT!
u = -234
Therefore, your answer is: [u = -234]
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Answer:
1: L = 5
W = 7
2: A = lw
3: 35
4: 18
5: You have to add them up because it is 1 shape broken up into different parts.
6: 53
<h3>
Answer: 5/9</h3>
As an approximate decimal, this is 0.5556 which converts to 55.56%
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Explanation:
Let's say there are 100 households (just for the sake of simplicity). We are told that 90% of them have answering machines. So that means 90 households have answering machines. In addition, 50 households have answering machines and call waiting. Those 50 households are part of the 90 mentioned previously.
We then select a house at random. Someone tells us (or we have some kind of prior knowledge) that whichever house is selected, they have an answering machine. We can ignore the 10 households that don't have an answering machine. Out of those 90 households, 50 have both features. So 50/90 = 5/9 is the probability of getting a household with both features.
The answer would be 1/2 or 50% if we didn't have the prior knowledge of the household having an answering machine. But with this prior knowledge, the conditions change and so does the probability.
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You could also compute 0.50/0.90 to get the same answer.
