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vitfil [10]
3 years ago
9

Mr.Molier is figuring out the semester averages for his history student. He can figure the average for 20 students in an hour. H

ow long does it take him to figure the average for each student?
Mathematics
1 answer:
Kruka [31]3 years ago
5 0

The answer is 3 because 60 divided by 20 is 3


You might be interested in
You have checked model income statements and estimate your payroll expense will be 36% of revenue. You expect sales to be $9,000
aksik [14]

Answer:

Budget annual payroll = $168,480

Step-by-step explanation:

Given:

Expect sales per week = $9,000

Revenue over sales = 36% = 0.36

Find:

Budget annual payroll = ?

Computation:

Assume number of week per year = 52

⇒ Budget annual payroll =  Expect sales per week × Number of week per year × Revenue over sales

⇒ Budget annual payroll = $9,000 × 52 × 0.36

⇒ Budget annual payroll = $168,480

3 0
3 years ago
The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

3 0
3 years ago
PLEASE HELP!!! I DONT HAVE ENOUGH POINTS TO POST MORE THAN ONCE!
Marat540 [252]

Answer:

-3.

Step-by-step explanation:

In the table, the y value goes down by -4 and then -2, for a total of -6.

We did this over a period of two units (To go from -1 to 1, we add 2).

-6/2 = -3.

-3 is the average rate of change over the interval.

3 0
3 years ago
Read 2 more answers
Hardy was given the scale drawing of the enlargement to find the scale factor and missing lengths. His work is shown below. Side
Maurinko [17]

Answer:

The correct answer is C on edgen  2021

Step-by-step explanation:

I legit just took a lucky guess and got it right lol

5 0
3 years ago
Read 2 more answers
A motorist drives for m hours at 120km/hr and n hours at 18km/hr. Altogether Somina drives 78km in 5 hours. Find m and n.​
nikdorinn [45]

Answer:

(0.118, 4.882)

Step-by-step explanation:

If a motorist drives for m hours at 120km/hr, then the Distance of the motorist is expressed as;

​Distance = Speed * time

​da = 120m

If he drives n hours at 18km/hr;

db = 18 * n

db = 18n

Speed of the motorist altogether is expressed as;

Speed =78km/5hrs

Speed = 15.6km/hr

SInce the total distnce is 78km

120m + 18n = 78 ....1 ..... * 1

If total time is 5hrs

m + n = 5....2 ...*18

Solve simultaneously

120m + 18n = 78

18m + 18n = 90

Subtract

120m - 18m = 78-90

102m = -12

m = 0.118 hrs

m =

Since m + n = 5

n = 5 - m

= 5 - 12/102

n = 4.882

Hence (m,n) is (0.118, 4.882)

3 0
3 years ago
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